I have a model with three fields
class MyModel(models.Model):
a = models.ForeignKey(A)
b = models.ForeignKey(B)
c = models.ForeignKey(C)
If you are happy to choose one of the duplicates arbitrarily, I think the following might do the trick. Perhaps not the most efficient but simple enough and I guess you only need to run this once. Please verify this all works yourself on some test data in case I've done something silly, since you are about to delete a bunch of data.
First we find groups of objects which form duplicates. For each group, (arbitrarily) pick a "master" that we are going to keep. Our chosen method is to pick the one with lowest pk
from django.db.models import Min, Count
master_pks = MyModel.objects.values('A', 'B', 'C'
).annotate(Min('pk'), count=Count('pk')
).filter(count__gt=1
).values_list('pk__min', flat=True)
we then loop over each master, and delete all its duplicates
masters = MyModel.objects.in_bulk( list(master_pks) )
for master in masters.values():
MyModel.objects.filter(a=master.a, b=master.b, c=master.c
).exclude(pk=master.pk).del_ACCIDENT_PREVENTION_ete()