Android camera intent FileUriExposedException for SDK >= 24

Question

I use this code to get a picture from camera and put it on imageview:

  private void openCamera()
{
    mMediaUri =getOutputMediaFileUri(MEDIA_TYPE_IMAGE);

             


        

Answer 1

Instead of return Uri.fromFile(mediaFile); do

return FileProvider.getUriForFile(MainActivity.this,
    BuildConfig.APPLICATION_ID + ".provider",
    mediaFile);

That would require you to add a provider to the AndroidManifest:

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
...
<application
    ...
    <provider
        android:name="android.support.v4.content.FileProvider"
        android:authorities="${applicationId}.provider"
        android:exported="false"
        android:grantUriPermissions="true">
        <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/provider_paths"/>
    </provider>
</application>

For AndroidX, use androidx.core.content.FileProvider

And then create a provider_paths.xml file in xml folder under res folder.

<?xml version="1.0" encoding="utf-8"?>
<paths xmlns:android="http://schemas.android.com/apk/res/android">
    <external-path name="external_files" path="."/>
</paths>

Read more: Full article

Answer 2

It can be done as simple as below . Put these 2 lines in onCreate of your activity.

StrictMode.VmPolicy.Builder newbuilder = new StrictMode.VmPolicy.Builder();
StrictMode.setVmPolicy(newbuilder.build());

URI exposure will be ignored by Vm I resolved my issue so.