SQL Query to find the last day of the month

Question

I need to find the last day of a month in the following format:

\"2013-05-31 00:00:00:000\"

Anybody please help out.

Answer 1

Declare @GivenDate datetime 
Declare @ResultDate datetime 
DEclare @EOMDate datetime 
Declare @Day int 
set @GivenDate=getdate() 
set @GivenDate= (dateadd(mm,1,@GivenDate)) 
set @Day =day(@GivenDate) 
set @ResultDate=dateadd(dd,-@Day+1,@GivenDate) 
select @EOMDate =dateadd(dd,-1 ,@ResultDate) 
select @EOMDate 

Answer 2

In Snowflake (and likely other SQL engines), you can use LAST_DAY.

select to_date('2015-05-08T23:39:20.123-07:00') as "DATE",
       last_day("DATE", 'MONTH') as "LAST DAY OF MONTH";

Which returns:

DATE         LAST DAY OF MONTH
2015-05-08          2015-05-31

Answer 3

select DATEADD(MONTH, DATEDIFF(MONTH, -1, GETDATE())-0, -1) LastDate

Answer 4

An excelent approach by me. Regards

DECLARE @MAXDATE INT=(SELECT MAX(DATEPART(YEAR,ORDERDATE)) FROM Orders)
DECLARE @MINDATE INT=(SELECT MIN(DATEPART(YEAR,ORDERDATE)) FROM Orders)
DECLARE @HORA INT=(SELECT MIN( DATEPART(HOUR,ORDERDATE)) FROM ORDERS)
DECLARE @DIA INT = 28

SELECT Employees.EmployeeID , Orders. OrderID , OrderDate  FROM Employees
INNER JOIN Orders 
ON Employees.EmployeeID = Orders.EmployeeID
Where  (DATEPART(YEAR,ORDERDATE)) >=@mindate and  (DATEPART(YEAR,ORDERDATE))<= @maxdate
and DATEPART(HOUR,ORDERDATE)=@HORA   and DATEPART(DAY,ORDERDATE) IN (30,31) OR DATEADD(DAY,0,DATEPART(DAY,ORDERDATE))=28 AND
DATEADD(MONTH,0,DATEPART(MONTH,ORDERDATE))=2
ORDER BY 1 ASC

Answer 5

dateadd(month,1+datediff(month,0,getdate()),-1)

To check run:

print dateadd(month,1+datediff(month,0,@date),-1)

Answer 6

Calculate the last date of the month is quite simple calculation -

1 - Find the total months count till today's date using DATEDIFF function -

Select DATEDIFF(MM,0,GETDATE())

Output - 1374, If getdate() output is "2014-07-23 19:33:46.850"

2 -Increment by 1 into total months count -

Select DATEDIFF(MM,0,GETDATE())+1

Output - 1375, If getdate() output is "2014-07-23 19:33:46.850"

3 - Get the first date of next month -

Select DATEADD(MM,DATEDIFF(MM,0,GETDATE())+1,0)

Output - '2014-08-01 00:00:00.000', If getdate() output is "2014-07-23 19:33:46.850"

4 - Subtract by -1 into the first date of next month, which will return last date of the current month -

Select DATEADD(DD,-1,DATEADD(MM,DATEDIFF(MM,0,GETDATE())+1,0))

Output - '2014-07-31 00:00:00.000', If getdate() output is "2014-07-23 19:33:46.850"

In the same manner of calculation we can achieve the -

1. Last date of next month
2. Last date of the previous month and so on.