Remove trailing decimal point & zeroes with Regex

Question

Is this the proper REGEX to remove trailing decimal and zeroes from a string? I can\'t get it to work. What am I missing?

1. 78.000 -> 78
2. 78.008 -> 78.008

Answer 1

Nope. Use this:

str.replaceAll("[.0]+$", "");

Answer 2

Get rid of the ^, which matches the start of the string. You also need to escape ., since it's a regex meta character that matches any character (except newlines):

str.replaceAll("\\.0*$", "");

Demo: http://ideone.com/RSJrO

Answer 3

You need to escape the ., as it is a special character in Regex that matches any character. You also have to remove the ^, which anchors at the beginning of the number.

str.replaceAll("\\.0*$", "");

You can use a lookbehind if you want to make sure there is a number in front of the dot, like this:

str.replaceAll("(?<=^\\d+)\\.0*$", "");

The lookbehind (the (?<=...) part) is not a part of the match, so it will not be replaced, but it still has to match for the rest of the regex to match.