Get the last day of the month in SQL

Question

I need to get the last day of the month given as a date in SQL. If I have the first day of the month, I can do something like this:

DATEADD(DAY, DATEADD(MONT         


        

Answer 1

My 2 cents:

select DATEADD(DAY,-1,DATEADD(MONTH,1,DATEADD(day,(0-(DATEPART(dd,'2008-02-12')-1)),'2008-02-12')))

Raj

Answer 2

You could get the days in the date by using the DAY() function:

dateadd(day, -1, dateadd(month, 1, dateadd(day, 1 - day(date), date)))

Answer 3

using sql server 2005, this works for me:

select dateadd(dd,-1,dateadd(mm,datediff(mm,0,YOUR_DATE)+1,0))

Basically, you get the number of months from the beginning of (SQL Server) time for YOUR_DATE. Then add one to it to get the sequence number of the next month. Then you add this number of months to 0 to get a date that is the first day of the next month. From this you then subtract a day to get to the last day of YOUR_DATE.

Answer 4

Based on the most voted answer at below link I came up with the following solution:

 declare  @mydate date= '2020-11-09';
  SELECT DATEADD(month, DATEDIFF(month, 0, @mydate)+1, -1) AS lastOfMonth

link: How can I select the first day of a month in SQL?

Answer 5

Using SQL Server, here is another way to find last day of month :

SELECT DATEADD(MONTH,1,GETDATE())- day(DATEADD(MONTH,1,GETDATE()))

Answer 6

Based on the statements:

SELECT DATEADD(MONTH, 1, @x)           -- Add a month to the supplied date @x

and

SELECT DATEADD(DAY,  0 - DAY(@x), @x)  -- Get last day of month previous to the supplied date @x

how about adding a month to date @x and then retrieving the last day of the month previous to that (i.e. The last day of the month of the supplied date)

DECLARE @x  DATE = '20-Feb-2012' 
SELECT DAY(DATEADD(DAY,  0 - DAY(DATEADD(MONTH, 1, @x)), DATEADD(MONTH, 1, @x)))

Note: This was test using SQL Server 2008 R2