Get the last day of the month in SQL

Question

I need to get the last day of the month given as a date in SQL. If I have the first day of the month, I can do something like this:

DATEADD(DAY, DATEADD(MONT         


        

Answer 1

Works in SQL server

Declare @GivenDate datetime
SET @GivenDate = GETDATE()

Select DATEADD(MM,DATEDIFF(MM, 0, @GivenDate),0) --First day of the month 

Select DATEADD(MM,DATEDIFF(MM, -1, @GivenDate),-1) --Last day of the month

Answer 2

Just extend your formula out a little bit:

dateadd(day, -1,
    dateadd(month, 1,
        cast(month('5/15/2009') as varchar(2)) + 
        '/1/' + 
        cast(year('5/15/2009') as varchar(4)))

Answer 3

WinSQL to get last day of last month (i.e today is 2017-02-09, returns 2017-01-31: Select dateadd(day,-day(today()),today())

Answer 4

I wrote following function, it works.

It returns datetime data type. Zero hour, minute, second, miliseconds.

CREATE Function [dbo].[fn_GetLastDate]
(
    @date datetime
)
returns datetime
as
begin

declare @result datetime

 select @result = CHOOSE(month(@date),  
 DATEADD(DAY, 31 -day(@date), @date),
 IIF(YEAR(@date) % 4 = 0, DATEADD(DAY, 29 -day(@date), @date), DATEADD(DAY, 28 -day(@date), @date)), 
 DATEADD(DAY, 31 -day(@date), @date) ,
 DATEADD(DAY, 30 -day(@date), @date), 
 DATEADD(DAY, 31 -day(@date), @date),
 DATEADD(DAY, 30 -day(@date), @date), 
 DATEADD(DAY, 31 -day(@date), @date),
 DATEADD(DAY, 31 -day(@date), @date),
 DATEADD(DAY, 30 -day(@date), @date),
 DATEADD(DAY, 31 -day(@date), @date),
 DATEADD(DAY, 30 -day(@date), @date), 
 DATEADD(DAY, 31 -day(@date), @date))

 return convert(date, @result)

end

It's very easy to use. 2 example:

select [dbo].[fn_GetLastDate]('2016-02-03 12:34:12')

select [dbo].[fn_GetLastDate](GETDATE())

Answer 5

Here's my version. No string manipulation or casting required, just one call each to the DATEADD, YEAR and MONTH functions:

DECLARE @test DATETIME
SET @test = GETDATE()  -- or any other date

SELECT DATEADD(month, ((YEAR(@test) - 1900) * 12) + MONTH(@test), -1)

Answer 6

I know this is a old question but here is another solution that works for me

SET @dtDate = "your date"
DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,@dtDate)+1,0))

And if some one is looking for different examples here is a link http://blog.sqlauthority.com/2007/08/18/sql-server-find-last-day-of-any-month-current-previous-next/

I hope this helps some one else. stackoverflow Rocks!!!!