Get the last day of the month in SQL

Question

I need to get the last day of the month given as a date in SQL. If I have the first day of the month, I can do something like this:

DATEADD(DAY, DATEADD(MONT         


        

Answer 1

For SQL server 2012 or above use EOMONTH to get the last date of month

SQL query to display end date of current month

DECLARE @currentDate DATE = GETDATE()
SELECT EOMONTH (@currentDate) AS CurrentMonthED

SQL query to display end date of Next month

DECLARE @currentDate DATE = GETDATE()
SELECT EOMONTH (@currentDate, 1 ) AS NextMonthED

Answer 2

This query can also be used.

DECLARE @SelectedDate DATE =  GETDATE()

SELECT DATEADD(DAY, - DAY(@SelectedDate), DATEADD(MONTH, 1 , @SelectedDate)) EndOfMonth

Answer 3

---Start/End of previous Month 
Declare @StartDate datetime, @EndDate datetime

set @StartDate = DATEADD(month, DATEDIFF(month, 0, GETDATE())-1,0) 
set @EndDate = EOMONTH (DATEADD(month, DATEDIFF(month, 0, GETDATE())-1,0)) 

SELECT @StartDate,@EndDate

Answer 4

Take some base date which is the 31st of some month e.g. '20011231'. Then use the
following procedure (I have given 3 identical examples below, only the @dt value differs).

declare @dt datetime;

set @dt = '20140312'

SELECT DATEADD(month, DATEDIFF(month, '20011231', @dt), '20011231');



set @dt = '20140208'

SELECT DATEADD(month, DATEDIFF(month, '20011231', @dt), '20011231');



set @dt = '20140405'

SELECT DATEADD(month, DATEDIFF(month, '20011231', @dt), '20011231');

Answer 5

This works for me, using Microsoft SQL Server 2005:

DATEADD(d,-1,DATEADD(mm, DATEDIFF(m,0,'2009-05-01')+1,0))

Answer 6

From SQL Server 2012 you can use the EOMONTH function.

Returns the last day of the month that contains the specified date, with an optional offset.

Syntax

EOMONTH ( start_date [, month_to_add ] ) 

How ... I can find the last day of the month for any given date?

SELECT EOMONTH(@SomeGivenDate)