Compose partial functions

Question

I have two PartialFunctions f and g. They have no side effects and are quick to execute. What\'s the best way to compose them into another partial func

Answer 1

Here's a shorter way than the linked question, taken from this thread:

  val f = Map("a" -> 1, "b" -> 2)                 

  val g = Map(1 -> 'c', 3 -> 'd')                 

  def andThenPartial[A, B, C](pf1: PartialFunction[A, B], pf2: PartialFunction[B, C]): PartialFunction[A, C] = {
    Function.unlift(pf1.lift(_) flatMap pf2.lift)
  }                                               

  val h = andThenPartial(f, g)            //> h  : PartialFunction[String,Char]

  h.isDefinedAt("a")                      //> res2: Boolean = true
  h.isDefinedAt("b")                      //> res3: Boolean = false
  h.lift("a")                             //> res4: Option[Char] = Some(c)
  h.lift("b")                             //> res5: Option[Char] = None

This can also be wrapped up as an implicit class, of course:

  implicit class ComposePartial[A, B](pf: PartialFunction[A, B]) {
    def andThenPartial[C](that: PartialFunction[B, C]): PartialFunction[A, C] =
      Function.unlift(pf.lift(_) flatMap that.lift)
  }

  val h2 = f andThenPartial g         //> h2  : PartialFunction[String,Char]

  h2.isDefinedAt("a")                 //> res6: Boolean = true
  h2.isDefinedAt("b")                 //> res7: Boolean = false
  h2.lift("a")                        //> res8: Option[Char] = Some(c)
  h2.lift("b")                        //> res9: Option[Char] = None

Answer 2

val h = f.mapValues(g)

But that only works for maps. I don't think there is a short way of doing that for any kind of partial function, you'll just have to create a new PartialFunction object manually.

edit: I see my above code is not what you wanted. But maybe this is better

val h = f.collect { case (k, v) if(g.contains(v)) => (k, g(v)) }