convert string to dict using list comprehension

Question

I have came across this problem a few times and can\'t seem to figure out a simple solution. Say I have a string

string = \"a=0 b=1 c=3\"

I wan

Answer 1

I sometimes like this approach, especially when the logic for making keys and values is more complicated:

s = "a=0 b=1 c=3"

def get_key_val(x):
    a,b = x.split('=')
    return a,int(b)

ans = dict(map(get_key_val,s.split()))

Answer 2

I would do this:

def kv(e): return (e[0], int(e[1]))
d = dict([kv(e.split("=")) for e in string.split(" ")])

Answer 3

Nowadays you should probably use a dictionary comprehension, introduced in 2.7:

mydict = {key: int(value) for key, value in (a.split('=') for a in mystring.split())}

The dictionary comprehension is faster and shinier (and, in my opinion, more readable).

from timeit import timeit

setup = """mystring = "a=0 b=1 c=3\""""
code1 = """mydict = dict((n,int(v)) for n,v in (a.split('=') for a in mystring.split()))""" # S.Lott's code
code2 = """mydict = {key: int(value) for key, value in (a.split('=') for a in mystring.split())}"""

print timeit(code1, setup=setup, number=10000) # 0.115524053574
print timeit(code2, setup=setup, number=10000) # 0.105328798294

Answer 4

Do you mean this?

>>> dict( (n,int(v)) for n,v in (a.split('=') for a in string.split() ) )
{'a': 0, 'c': 3, 'b': 1}

Answer 5

Try the next:

dict([x.split('=') for x in s.split()])

Answer 6

from cgi import parse_qsl
text = "a=0 b=1 c=3"
dic = dict((k, int(v)) for k, v in parse_qsl(text.replace(' ', '&')))
print dic

prints

{'a': 0, 'c': 3, 'b': 1}