how to remove Xml version string from String

Question

I have read Xml File using code given below-

  String XmlString = \"\";
  String resourcePath=FilePathHelper.getResourceFilePath(request);



        BufferedRea         


        

Answer 1

substring with first index of '>' + 1 ( +1 to get to next char), wont it give you end of xml version? Though it is not clean way of doing this.

Answer 2

Change your regular expression to

XmlString=XmlString.replaceAll("\\<\\?xml(.+?)\\?\\>", "").trim();

Answer 3

String xmlString = readXml();
int p1 = xmlString.indexOf("<?xml ");
int p2 = xmlString.indexOf("?>");
if ( p1 != -1 && p2 != -1 && p2>p1){
   xmlString=xmlString.substring(0,p1)+xmlString(p2+2);
}

private String readXml(){
   //TOTO from file or any-pipeline read,convert to String....
}

Answer 4

Another way would we to do it like this:

XmlString = XmlString.substring(XmlString.indexOf("<Template>"))

edit: indexOf() instead of firstIndexOf()

Answer 5

if(XmlString .contains("<?xml")){
  XmlString = XmlString.substring(XmlString.indexOf("?>")+2);
}