I have the following data in my database:
|NO | model | date |
+---+-------+----------+
|1 | bee |2011-12-01|
|2 | bee |2011-12-05|
|3 | bee |2
This should work:
SELECT model, date FROM doc GROUP BY model ORDER BY date DESC
It just sort the dates from last to first and by grouping it only grabs the first one.
Are you looking for the max date for each model?
SELECT model, max(date) FROM doc
GROUP BY model
If you're looking for all models matching the max date of the entire table...
SELECT model, date FROM doc
WHERE date IN (SELECT max(date) FROM doc)
[--- Added ---]
For those who want to display details from every record matching the latest date within each model group (not summary data, as asked for in the OP):
SELECT d.model, d.date, d.color, d.etc FROM doc d
WHERE d.date IN (SELECT max(d2.date) FROM doc d2 WHERE d2.model=d.model)
MySQL 8.0 and newer supports the OVER
clause, producing the same results a bit faster for larger data sets.
SELECT model, date, color, etc FROM (SELECT model, date, color, etc,
max(date) OVER (PARTITION BY model) max_date FROM doc) predoc
WHERE date=max_date;
try this:
SELECT model, date
FROM doc
WHERE date = (SELECT MAX(date)
FROM doc GROUP BY model LIMIT 0, 1)
GROUP BY model
And why not to use this ?
SELECT model, date FROM doc ORDER BY date DESC LIMIT 1
Subquery giving dates. We are not linking with the model. So below query solves the problem.
If there are duplicate dates/model can be avoided by the following query.
select t.model, t.date
from doc t
inner join (select model, max(date) as MaxDate from doc group by model)
tm on t.model = tm.model and t.date = tm.MaxDate
You can try using max() in subquery, something like this :
SELECT model, date
FROM doc
WHERE date in (SELECT MAX(date) from doc GROUP BY model);