Is there any equivalent to str.split
in Python that also returns the delimiters?
I need to preserve the whitespace layout for my output after processing som
the re
module provides this functionality:
>>> import re
>>> re.split('(\W+)', 'Words, words, words.')
['Words', ', ', 'words', ', ', 'words', '.', '']
(quoted from the Python documentation).
For your example (split on whitespace), use re.split('(\s+)', '\tThis is an example')
.
The key is to enclose the regex on which to split in capturing parentheses. That way, the delimiters are added to the list of results.
Edit: As pointed out, any preceding/trailing delimiters will of course also be added to the list. To avoid that you can use the .strip()
method on your input string first.
How about
import re
splitter = re.compile(r'(\s+|\S+)')
splitter.findall(s)
>>> re.compile(r'(\s+)').split("\tthis is an example")
['', '\t', 'this', ' ', 'is', ' ', 'an', ' ', 'example']
Thanks guys for pointing for the re
module, I'm still trying to decide between that and using my own function that returns a sequence...
def split_keep_delimiters(s, delims="\t\n\r "):
delim_group = s[0] in delims
start = 0
for index, char in enumerate(s):
if delim_group != (char in delims):
delim_group ^= True
yield s[start:index]
start = index
yield s[start:index+1]
If I had time I'd benchmark them xD
Have you looked at pyparsing? Example borrowed from the pyparsing wiki:
>>> from pyparsing import Word, alphas
>>> greet = Word(alphas) + "," + Word(alphas) + "!"
>>> hello1 = 'Hello, World!'
>>> hello2 = 'Greetings, Earthlings!'
>>> for hello in hello1, hello2:
... print (u'%s \u2192 %r' % (hello, greet.parseString(hello))).encode('utf-8')
...
Hello, World! → (['Hello', ',', 'World', '!'], {})
Greetings, Earthlings! → (['Greetings', ',', 'Earthlings', '!'], {})