Suppose I have something like this :
try code_that_fails()
catch _:_ -> .....
How do I print the stacktrace in the catch block? That block c
An answer for your question is:
io:format("Backtrace ~p~n", [erlang:get_stacktrace()])
The current function is at the head of the list. Read more in man 3erl erlang
or erlang:get_stacktrace/0
From Erlang 21.0 onwards, there's a new official way to get the stack trace. An optional pattern match in the try expression on the third parameter in the exception, which will contain the stack trace:
try
code_that_fails()
catch
_:_:Stacktrace ->
erlang:display(Stacktrace)
end
For versions of Erlang/OTP 20 and below, you need to use get_stacktrace/0, which allows you to get the stacktrace of the last exception in the calling process:
try
code_that_fails()
catch
_:_ ->
erlang:display(erlang:get_stacktrace())
end
In your example, you don't need the try
; you can just do
result = (catch code_that_fails()).
If an exception is raised, catch
returns a tuple that contains the error code and stack trace.
Note that this is generally considered bad practice as it can mask exceptions. The stacktrace approach described in another answer is almost certainly what you want.
try
is an extension of the original catch
functionality; if you use it, you need to specify clauses for each exception type you would like to catch, and handle them appropriately. See sections 6.18/6.19 of the Erlang reference manual for details and clear examples.