Spring MVC: How to return custom 404 errorpages?

Question

I\'m looking for a clean way to return customized 404 errorpages in Spring 4 when a requested resource was not found. Queries to different domain types should result in diff

Answer 1

modified your web.xml file.Using following code.

<display-name>App Name </display-name>
<error-page>
<error-code>500</error-code>
<location>/error500.jsp</location>
</error-page>

<error-page>
<error-code>404</error-code>
<location>/error404.jsp</location>
</error-page>

Access this by following code.

response.sendError(508802,"Error Message");

Now add this code in web.xml.

<error-page>
<error-code>508802</error-code>
<location>/error500.jsp</location>
</error-page>

Answer 2

Simple answer for 100% free xml:

1. Set properties for DispatcherServlet

   public class SpringMvcInitializer extends AbstractAnnotationConfigDispatcherServletInitializer {
   
   @Override
   protected Class<?>[] getRootConfigClasses() {
       return new Class[] { RootConfig.class  };
   }
   
   @Override
   protected Class<?>[] getServletConfigClasses() {
       return new Class[] {AppConfig.class  };
   }
   
   @Override
   protected String[] getServletMappings() {
       return new String[] { "/" };
   }
   
   //that's important!!
   @Override
   protected void customizeRegistration(ServletRegistration.Dynamic registration) {
       boolean done = registration.setInitParameter("throwExceptionIfNoHandlerFound", "true"); // -> true
       if(!done) throw new RuntimeException();
   }
   

   }

2. Create @ControllerAdvice:

   @ControllerAdvice
   public class AdviceController {
   
   @ExceptionHandler(NoHandlerFoundException.class)
   public String handle(Exception ex) {
       return "redirect:/404";
   }
   
   @RequestMapping(value = {"/404"}, method = RequestMethod.GET)
   public String NotFoudPage() {
       return "404";
   
   }
   

   }

3. Create 404.jsp page with any content

That's all.