Reading from a ZipInputStream into a ByteArrayOutputStream

Question

I am trying to read a single file from a java.util.zip.ZipInputStream, and copy it into a java.io.ByteArrayOutputStream (so that I can then create a

Answer 1

You could implement your own wrapper around the ZipInputStream that ignores close() and hand that off to the third-party library.

thirdPartyLib.handleZipData(new CloseIgnoringInputStream(zipStream));


class CloseIgnoringInputStream extends InputStream
{
    private ZipInputStream stream;

    public CloseIgnoringInputStream(ZipInputStream inStream)
    {
        stream = inStream;
    }

    public int read() throws IOException {
        return stream.read();
    }

    public void close()
    {
        //ignore
    }

    public void reallyClose() throws IOException
    {
        stream.close();
    }
}

Answer 2

Please try code bellow

private static byte[] getZipArchiveContent(File zipName) throws WorkflowServiceBusinessException {

  BufferedInputStream buffer = null;
  FileInputStream fileStream = null;
  ByteArrayOutputStream byteOut = null;
  byte data[] = new byte[BUFFER];

  try {
   try {
    fileStream = new FileInputStream(zipName);
    buffer = new BufferedInputStream(fileStream);
    byteOut = new ByteArrayOutputStream();

    int count;
    while((count = buffer.read(data, 0, BUFFER)) != -1) {
     byteOut.write(data, 0, count);
    }
   } catch(Exception e) {
    throw new WorkflowServiceBusinessException(e.getMessage(), e);
   } finally {
    if(null != fileStream) {
     fileStream.close();
    }
    if(null != buffer) {
     buffer.close();
    }
    if(null != byteOut) {
     byteOut.close();
    }
   }
  } catch(Exception e) {
   throw new WorkflowServiceBusinessException(e.getMessage(), e);
  }
  return byteOut.toByteArray();

 }

Answer 3

Your loop looks valid - what does the following code (just on it's own) return?

zipStream.read(tempBuffer)

if it's returning -1, then the zipStream is closed before you get it, and all bets are off. It's time to use your debugger and make sure what's being passed to you is actually valid.

When you call getNextEntry(), does it return a value, and is the data in the entry meaningful (i.e. does getCompressedSize() return a valid value)? IF you are just reading a Zip file that doesn't have read-ahead zip entries embedded, then ZipInputStream isn't going to work for you.

Some useful tidbits about the Zip format:

Each file embedded in a zip file has a header. This header can contain useful information (such as the compressed length of the stream, it's offset in the file, CRC) - or it can contain some magic values that basically say 'The information isn't in the stream header, you have to check the Zip post-amble'.

Each zip file then has a table that is attached to the end of the file that contains all of the zip entries, along with the real data. The table at the end is mandatory, and the values in it must be correct. In contrast, the values embedded in the stream do not have to be provided.

If you use ZipFile, it reads the table at the end of the zip. If you use ZipInputStream, I suspect that getNextEntry() attempts to use the entries embedded in the stream. If those values aren't specified, then ZipInputStream has no idea how long the stream might be. The inflate algorithm is self terminating (you actually don't need to know the uncompressed length of the output stream in order to fully recover the output), but it's possible that the Java version of this reader doesn't handle this situation very well.

I will say that it's fairly unusual to have a servlet returning a ZipInputStream (it's much more common to receive an inflatorInputStream if you are going to be receiving compressed content.

Answer 4

Check if the input stream is positioned in the begging.

Otherwise, as implementation: I do not think that you need to write to the result stream while you are reading, unless you process this exact stream in another thread.

Just create a byte array, read the input stream, then create the output stream.