I am trying to get my footer to show on top of the footer background, but z-index seems not to be working. Does anyone see what is wrong with it? http://jsfiddle.net/f2ySC/
You have to explicitly define the position
property:
.footerBox {
background-color: #FFFFFF;
border: 10px solid #DDDDDD;
margin: 10px 0 -200px -10px;
width: 1185px;
z-index: 1000;
position:relative;
}
http://jsfiddle.net/f2ySC/1/
This brings the footer into the current stacking context
:
... The root element forms the root stacking context. Other stacking contexts are generated by any positioned element (including relatively positioned elements) having a computed value of 'z-index' other than 'auto'. Stacking contexts are not necessarily related to containing blocks. In future levels of CSS, other properties may introduce stacking contexts, for example 'opacity' ...
http://www.w3.org/TR/CSS2/visuren.html#z-index
On footerBox set the position
attribute to absolute
Your new code should read as follows
.footerBox {
background-color: #FFFFFF;
border: 10px solid #DDDDDD;
margin: 10px 0 -200px -10px;
width: 1185px;
z-index: 1000;
position: absolute;
}
See a demo here
Using position: relative
also works
using negative margin is not a good practice. z-index:-1; works it just display the content on the background of another div :)
Is this the effect you are looking for? Updated example
I added position: relative;
to #footerBack
and .footerBox
to enable z-index