Regular Expression for Range (2-16)

Question

I want to match a number between 2-16, spanning 1 digit to 2 digits.

Regular-Expressions.info has examples for 1 or 2 digit ranges, but not something that spans both:

Answer 1

^([2-9]|1[0-6])$

will match either a single digit between 2 and 9 inclusive, or a 1 followed by a digit between 0 and 6, inclusive.

Answer 2

Use the python package regex_engine for generate regular expressions for numerical ranges

You can install this package by using pip

pip install regex-engine

from regex_engine import generator

generate = generator()

regex = generate.numerical_range(2,16)

print(regex)

^([2-9]|1[0-6])$

You can also generate regexes for floating point and negative ranges

from regex_engine import generator

generate = generator()

regex1 = generate.numerical_range(5,89)
regex2 = generate.numerical_range(81.78,250.23)
regex3 = generate.numerical_range(-65,12)

Answer 3

With delimiters (out of habit): /^([2-9]|1[0-6])$/

The regex itself is just: ^([2-9]|1[0-6])$

Answer 4

^([2-9]|1[0-6])$

(Edit: Removed quotes for clarification.)

Answer 5

(^[2-9]$|^1[0-6]$)

By specifying start and stop for each set of numbers you are looking for your regex won't also return 36, 46, ... and so on. I tried the above solution and found that this works best for staying within the range of 2-16.