Shell script using curl to loop through urls

Question

I\'ve been trying to create a simple script that will take a list of queries from a .txt file, append the main url variable, then scrape the content and output it to a text file

Answer 1

You've got nested quotes, try something like this:

#!/bin/bash

url=https://www.google.fr/?q=
while read query
do
    content=$(curl "{$url}${query}")
    echo $query
    echo $content >> output.txt
done < query.txt

Answer 2

Use more quotes !

• http://mywiki.wooledge.org/Quotes
• http://mywiki.wooledge.org/Arguments
• http://wiki.bash-hackers.org/syntax/words

Try this instead :

url="example.com/?q="
for i in $(cat query.txt); do
    content="$(curl -s "$url/$i")"
    echo "$content" >> output.txt
done