How to use swift flatMap to filter out optionals from an array

后端 未结 5 1934
野的像风
野的像风 2021-02-05 05:14

I\'m a little confused around flatMap (added to Swift 1.2)

Say I have an array of some optional type e.g.

let possibles:[Int?] = [nil, 1, 2, 3, nil, nil         


        
相关标签:
5条回答
  • 2021-02-05 05:53

    I still like the first solution, which creates only one intermediate array. It can slightly more compact be written as

    let filtermap = possibles.filter({ $0 != nil }).map({ $0! })
    

    But flatMap() without type annotation and without forced unwrapping is possible:

    var flatmap3 = possibles.flatMap {
        flatMap($0, { [$0] }) ?? []
    }
    

    The outer flatMap is the array method

    func flatMap<U>(transform: @noescape (T) -> [U]) -> [U]
    

    and the inner flatMap is the function

    func flatMap<T, U>(x: T?, f: @noescape (T) -> U?) -> U?
    

    Here is a simple performance comparison (compiled in Release mode). It shows that the first method is faster, approximately by a factor of 10:

    let count = 1000000
    let possibles : [Int?] = map(0 ..< count) { $0 % 2 == 0 ? $0 : nil }
    
    let s1 = NSDate()
    let result1 = possibles.filter({ $0 != nil }).map({ $0! })
    let e1 = NSDate()
    println(e1.timeIntervalSinceDate(s1))
    // 0.0169369578361511
    
    let s2 = NSDate()
    var result2 = possibles.flatMap {
        flatMap($0, { [$0] }) ?? []
    }
    let e2 = NSDate()
    println(e2.timeIntervalSinceDate(s2))
    // 0.117663979530334
    
    0 讨论(0)
  • 2021-02-05 05:54

    Related to the question. If you are applying flatMap to an optional array, do not forget to optionally or force unwrap your array otherwise it will call flatMap on Optional and not objects conforming to Sequence protocol. I made that mistake once, E.g. when you want to remove empty strings:

    var texts: [String]? = ["one", "two", "", "three"] // has unwanted empty string
    
    let notFlatMapped = texts.flatMap({ $0.count > 0 ? $0 : nil })
    // ["one", "two", "", "three"], not what we want - calls flatMap on Optional
    
    let flatMapped = texts?.flatMap({ $0.count > 0 ? $0 : nil })
    // ["one", "two", "three"], that's what we want, calls flatMap on Array
    
    0 讨论(0)
  • 2021-02-05 06:04

    You could use reduce:

    let flattened = possibles.reduce([Int]()) { 
            if let x = $1 { return $0 + [x] } else { return $0 } 
        }
    

    You are still kind of declaring the type, but it's slightly less obtrusive.

    0 讨论(0)
  • 2021-02-05 06:10

    Since this is something I seem to end up doing quite a lot I'm exploring a generic function to do this.

    I tried to add an extension to Array so I could do something like possibles.unwraped but couldn't figure out how to make an extension on an Array. Instead used a custom operator -- hardest part here was trying to figure out which operator to choose. In the end I chose >! to show that the array is being filtered > and then unwrapped !.

    let possibles:[Int?] = [nil, 1, 2, 3, nil, nil, 4, 5]
    
    postfix operator >! {}
    
    postfix func >! <T>(array: Array<T?>) -> Array<T> {
        return array.filter({ $0 != nil }).map({ $0! })
    }
    
    possibles>!
    // [1, 2, 3, 4, 5]
    
    0 讨论(0)
  • 2021-02-05 06:16

    Since Swift 4.1 you can use compactMap:

    let possibles:[Int?] = [nil, 1, 2, 3, nil, nil, 4, 5]
    let actuals = possibles.compactMap { $0 }
    

    (Swift 4.1 replaced some overloads of flatMap with compactmap. If you are interested in more detail on this then see for example: https://useyourloaf.com/blog/replacing-flatmap-with-compactmap/ )

    With Swift 2 b1, you can simply do

    let possibles:[Int?] = [nil, 1, 2, 3, nil, nil, 4, 5]
    let actuals = possibles.flatMap { $0 }
    

    For earlier versions, you can shim this with the following extension:

    extension Array {
        func flatMap<U>(transform: Element -> U?) -> [U] {
            var result = [U]()
            result.reserveCapacity(self.count)
            for item in map(transform) {
                if let item = item {
                    result.append(item)
                }
            }
            return result
        }
    }
    

    One caveat (which is also true for Swift 2) is that you might need to explicitly type the return value of the transform:

    let actuals = ["a", "1"].flatMap { str -> Int? in
        if let int = str.toInt() {
            return int
        } else {
            return nil
        }
    }
    assert(actuals == [1])
    

    For more info, see http://airspeedvelocity.net/2015/07/23/changes-to-the-swift-standard-library-in-2-0-betas-2-5/

    0 讨论(0)
提交回复
热议问题