How can I apply an offset on the current time in python?
In other terms, be able to get the current time minus x hours and/or minus m minutes and/or minus s secondes a
Use a datetime.datetime(), then add or subtract datetime.timedelta() instances.
>>> import datetime
>>> t = datetime.datetime.now()
>>> t - datetime.timedelta(hours=1, minutes=10)
datetime.datetime(2012, 12, 26, 17, 18, 52, 167840)
timedelta()
arithmetic is not supported for datetime.time()
objects; if you need to use offsets from an existing datetime.time()
object, just use datetime.datetime.combine()
to form a datetime.datetime()
instance, do your calculations, and 'extract' the time again with the .time()
method:
>>> t = datetime.time(1, 2)
>>> dt = datetime.datetime.combine(datetime.date.today(), t)
>>> dt
datetime.datetime(2012, 12, 26, 1, 2)
>>> dt -= datetime.timedelta(hours=5)
>>> dt.time()
datetime.time(20, 2)