Removing spaces from a variable input using PowerShell 4.0

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青春惊慌失措
青春惊慌失措 2021-02-05 03:59

I\'ve tried a few things already but they don\'t seem to work for some reason.

Basically what I\'m attempting to do is have a user input a value using the \"Read-host\

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  • 2021-02-05 04:21

    You also have the Trim, TrimEnd and TrimStart methods of the System.String class. The trim method will strip whitespace (with a couple of Unicode quirks) from the leading and trailing portion of the string while allowing you to optionally specify the characters to remove.

    #Note there are spaces at the beginning and end
    Write-Host " ! This is a test string !%^ "
     ! This is a test string !%^
    #Strips standard whitespace
    Write-Host " ! This is a test string !%^ ".Trim()
    ! This is a test string !%^
    #Strips the characters I specified
    Write-Host " ! This is a test string !%^ ".Trim('!',' ')
    This is a test string !%^
    #Now removing ^ as well
    Write-Host " ! This is a test string !%^ ".Trim('!',' ','^')
    This is a test string !%
    Write-Host " ! This is a test string !%^ ".Trim('!',' ','^','%')
    This is a test string
    #Powershell even casts strings to character arrays for you
    Write-Host " ! This is a test string !%^ ".Trim('! ^%')
    This is a test string
    

    TrimStart and TrimEnd work the same way just only trimming the start or end of the string.

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  • 2021-02-05 04:23

    The Replace operator means Replace something with something else; do not be confused with removal functionality.

    Also you should send the result processed by the operator to a variable or to another operator. Neither .Replace(), nor -replace modifies the original variable.

    To remove all spaces, use 'Replace any space symbol with empty string'

    $string = $string -replace '\s',''
    

    To remove all spaces at the beginning and end of the line, and replace all double-and-more-spaces or tab symbols to spacebar symbol, use

    $string = $string -replace '(^\s+|\s+$)','' -replace '\s+',' '
    

    or the more native System.String method

    $string = $string.Trim()
    

    Regexp is preferred, because ' ' means only 'spacebar' symbol, and '\s' means 'spacebar, tab and other space symbols'. Note that $string.Replace() does 'Normal' replace, and $string -replace does RegEx replace, which is more heavy but more functional.

    Note that RegEx have some special symbols like dot (.), braces ([]()), slashes (\), hats (^), mathematical signs (+-) or dollar signs ($) that need do be escaped. ( 'my.space.com' -replace '\.','-' => 'my-space-com'. A dollar sign with a number (ex $1) must be used on a right part with care

    '2033' -replace '(\d+)',$( 'Data: $1')
    Data: 2033
    

    UPDATE: You can also use $str = $str.Trim(), along with TrimEnd() and TrimStart(). Read more at System.String MSDN page.

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  • 2021-02-05 04:25

    You're close. You can strip the whitespace by using the replace method like this:

    $answer.replace(' ','')

    There needs to be no space or characters between the second set of quotes in the replace method (replacing the whitespace with nothing).

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  • 2021-02-05 04:31

    If the string is

    $STR = 'HELLO WORLD'
    

    and you want to remove the empty space between 'HELLO' and 'WORLD'

    $STR.replace(' ','')
    

    replace takes the string and replaces white space with empty string (of length 0), in other words the white space is just deleted.

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  • 2021-02-05 04:32

    You can use:

    $answer.replace(' ' , '')
    

    or

    $answer -replace " ", ""
    

    if you want to remove all whitespace you can use:

    $answer -replace "\s", ""
    
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