I\'m running a service, where Swagger UI is accessible at:
http://serviceURL/swagger-ui.html
However, it is behind a proxy, such as:
@Bean
public Docket newsApi(ServletContext servletContext) {
return new Docket(DocumentationType.SWAGGER_2).pathProvider(new RelativePathProvider(servletContext) {
@Override
public String getApplicationBasePath() {
return "/serviceName" + super.getApplicationBasePath();
}
}).host("proxyURL");
}
Using spring fox 2.9.2, using solution mentioned by other users is not works.
What is not working:
I don't know why they are not work, but in my project that using Springboot 2.1.6.RELEASE and Spring 5.1.8.RELEASE, the two solution above is being ignored.
So, I am trying another approach: https://github.com/springfox/springfox/issues/2817#issuecomment-517753110
According to the github issue comment, I need to override Springfox json serialize class and thank god this works. Here is the code example:
import io.swagger.models.Swagger;
import org.springframework.context.annotation.Primary;
import org.springframework.core.env.Environment;
import org.springframework.stereotype.Component;
import springfox.documentation.spring.web.json.JacksonModuleRegistrar;
import springfox.documentation.spring.web.json.Json;
import springfox.documentation.spring.web.json.JsonSerializer;
import java.util.Arrays;
import java.util.List;
import static io.github.jhipster.config.JHipsterConstants.SPRING_PROFILE_PRODUCTION;
@Component
@Primary
public class CustomBasePathSerialize extends JsonSerializer {
// this injection is optional, if you don't need to
// add basePath based on active profile, remove this.
private final Environment env;
public CustomBasePathSerialize(List<JacksonModuleRegistrar> modules,
Environment env) {
super(modules);
this.env = env;
}
@Override
public Json toJson(Object toSerialize) {
if (toSerialize instanceof Swagger) {
Swagger swagger = (Swagger) toSerialize;
String basePath = "/serviceName";
List<String> profiles = Arrays.asList(env.getActiveProfiles());
// OPTIONAL: you can change basePath if you have difference path
// on any Spring profile, for example prod:
if (profiles.contains(SPRING_PROFILE_PRODUCTION)) {
basePath = "/";
}
swagger.basePath(basePath);
}
return super.toJson(toSerialize);
}
}
Take care to replace the
package
(which need to be the one containing your REST controllers), thehost
, and thePATH
you need
@Configuration
@EnableSwagger2
public class SwaggerConfiguration implements WebMvcConfigurer {
public static final String PATH = "/serviceName";
@Bean
public Docket api() {
final var package = "com.martin.rest";
final var host = "localhost:8080";
return new Docket(DocumentationType.SWAGGER_2)
.host(host)
.select()
.apis(RequestHandlerSelectors.basePackage(package))
.paths(PathSelectors.any())
.build();
}
@Override
public void addViewControllers(ViewControllerRegistry registry) {
final var apiDocs = "/v2/api-docs";
final var configUi = "/swagger-resources/configuration/ui";
final var configSecurity = "/swagger-resources/configuration/security";
final var resources = "/swagger-resources";
registry.addRedirectViewController(PATH + apiDocs, apiDocs).setKeepQueryParams(true);
registry.addRedirectViewController(PATH + resources, resources);
registry.addRedirectViewController(PATH + configUi, configUi);
registry.addRedirectViewController(PATH + configSecurity, configSecurity);
registry.addRedirectViewController(PATH, "/");
}
@Override
public void addResourceHandlers(ResourceHandlerRegistry registry) {
registry.addResourceHandler(PATH + "/**").addResourceLocations("classpath:/META-INF/resources/");
}
}
Edit pour application.properties
file:
server.servlet.context-path=/serviceName
Or if you have an application.yml
file:
server:
servlet:
context-path: /serviceName
Warning: It will change the base path of all your web services, not only Swagger