Convert two lists into a dictionary

Question

Imagine that you have:

keys = [\'name\', \'age\', \'food\']
values = [\'Monty\', 42, \'spam\']

What is the simplest way to produce the foll

Answer 1

If you need to transform keys or values before creating a dictionary then a generator expression could be used. Example:

>>> adict = dict((str(k), v) for k, v in zip(['a', 1, 'b'], [2, 'c', 3])) 

Take a look Code Like a Pythonista: Idiomatic Python.

Answer 2

method without zip function

l1 = [1,2,3,4,5]
l2 = ['a','b','c','d','e']
d1 = {}
for l1_ in l1:
    for l2_ in l2:
        d1[l1_] = l2_
        l2.remove(l2_)
        break  

print (d1)


{1: 'd', 2: 'b', 3: 'e', 4: 'a', 5: 'c'}

Answer 3

>>> keys = ('name', 'age', 'food')
>>> values = ('Monty', 42, 'spam')
>>> dict(zip(keys, values))
{'food': 'spam', 'age': 42, 'name': 'Monty'}

Answer 4

For those who need simple code and aren’t familiar with zip:

List1 = ['This', 'is', 'a', 'list']
List2 = ['Put', 'this', 'into', 'dictionary']

This can be done by one line of code:

d = {List1[n]: List2[n] for n in range(len(List1))}

Answer 5

Like this:

>>> keys = ['a', 'b', 'c']
>>> values = [1, 2, 3]
>>> dictionary = dict(zip(keys, values))
>>> print(dictionary)
{'a': 1, 'b': 2, 'c': 3}

Voila :-) The pairwise dict constructor and zip function are awesomely useful: https://docs.python.org/3/library/functions.html#func-dict

Answer 6

with Python 3.x, goes for dict comprehensions

keys = ('name', 'age', 'food')
values = ('Monty', 42, 'spam')

dic = {k:v for k,v in zip(keys, values)}

print(dic)

More on dict comprehensions here, an example is there:

>>> print {i : chr(65+i) for i in range(4)}
    {0 : 'A', 1 : 'B', 2 : 'C', 3 : 'D'}