From time to time I see an enum like the following:
[Flags]
public enum Options
{
None = 0,
Option1 = 1,
Option2 = 2,
Option3 = 4,
Op
Flags are used when an enumerable value represents a collection of enum members.
here we use bitwise operators, | and &
Example
[Flags]
public enum Sides { Left=0, Right=1, Top=2, Bottom=3 }
Sides leftRight = Sides.Left | Sides.Right;
Console.WriteLine (leftRight);//Left, Right
string stringValue = leftRight.ToString();
Console.WriteLine (stringValue);//Left, Right
Sides s = Sides.Left;
s |= Sides.Right;
Console.WriteLine (s);//Left, Right
s ^= Sides.Right; // Toggles Sides.Right
Console.WriteLine (s); //Left
You can also do this
[Flags]
public enum MyEnum
{
None = 0,
First = 1 << 0,
Second = 1 << 1,
Third = 1 << 2,
Fourth = 1 << 3
}
I find the bit-shifting easier than typing 4,8,16,32 and so on. It has no impact on your code because it's all done at compile time
@Nidonocu
To add another flag to an existing set of values, use the OR assignment operator.
Mode = Mode.Read;
//Add Mode.Write
Mode |= Mode.Write;
Assert.True(((Mode & Mode.Write) == Mode.Write)
&& ((Mode & Mode.Read) == Mode.Read)));
Flags allow you to use bitmasking inside your enumeration. This allows you to combine enumeration values, while retaining which ones are specified.
[Flags]
public enum DashboardItemPresentationProperties : long
{
None = 0,
HideCollapse = 1,
HideDelete = 2,
HideEdit = 4,
HideOpenInNewWindow = 8,
HideResetSource = 16,
HideMenu = 32
}
I asked recently about something similar.
If you use flags you can add an extension method to enums to make checking the contained flags easier (see post for detail)
This allows you to do:
[Flags]
public enum PossibleOptions : byte
{
None = 0,
OptionOne = 1,
OptionTwo = 2,
OptionThree = 4,
OptionFour = 8,
//combinations can be in the enum too
OptionOneAndTwo = OptionOne | OptionTwo,
OptionOneTwoAndThree = OptionOne | OptionTwo | OptionThree,
...
}
Then you can do:
PossibleOptions opt = PossibleOptions.OptionOneTwoAndThree
if( opt.IsSet( PossibleOptions.OptionOne ) ) {
//optionOne is one of those set
}
I find this easier to read than the most ways of checking the included flags.
Combining answers https://stackoverflow.com/a/8462/1037948 (declaration via bit-shifting) and https://stackoverflow.com/a/9117/1037948 (using combinations in declaration) you can bit-shift previous values rather than using numbers. Not necessarily recommending it, but just pointing out you can.
Rather than:
[Flags]
public enum Options : byte
{
None = 0,
One = 1 << 0, // 1
Two = 1 << 1, // 2
Three = 1 << 2, // 4
Four = 1 << 3, // 8
// combinations
OneAndTwo = One | Two,
OneTwoAndThree = One | Two | Three,
}
You can declare
[Flags]
public enum Options : byte
{
None = 0,
One = 1 << 0, // 1
// now that value 1 is available, start shifting from there
Two = One << 1, // 2
Three = Two << 1, // 4
Four = Three << 1, // 8
// same combinations
OneAndTwo = One | Two,
OneTwoAndThree = One | Two | Three,
}
Confirming with LinqPad:
foreach(var e in Enum.GetValues(typeof(Options))) {
string.Format("{0} = {1}", e.ToString(), (byte)e).Dump();
}
Results in:
None = 0
One = 1
Two = 2
OneAndTwo = 3
Three = 4
OneTwoAndThree = 7
Four = 8