Please explain closures, or binding the loop counter to the function scope

Question

I\'ve seen programmers assign events listeners inside loops, using the counter. I believe this is the syntax:

for(var i=0; i < someArray.length; i++){
   some         


        

Answer 1

The (function(i))(i) syntax creates an anonymous function and then immediately executes it.

Usually you'll do this to create a new function every time through the loop, that has its own copy of the variable instead of every event handler sharing the same variable.

So for example:

for(int i = 0; i < 10; i++)
    buttons[i].click = function() { doFoo(i); };

Often catches people out, because no matter what button you click on, doFoo(10) is called.

Whereas:

for(int i = 0; i < 10; i++)
    buttons[i].click = (function(i){ return function() { doFoo(i); };)(i);

Creates a new instance of the inner function (with its own value of i) for each iteration, and works as expected.

Answer 2

This is done because JavaScript only has function scope, not block scope. Hence, every variable you declare in a loop is in the function's scope and every closure you create has access to the very same variable.

So the only way to create a new scope is to call a function and that is what

(function(i){/* Some code using i */}(i))

is doing.

Note that your example misses an important part: The immediate function has to return another function which will be the click handler:

someArray[i].onclick = (function(i){
    return function() {
       /* Some code using i */
    }
}(i));

The immediate function is nothing special. It is somehow inlining function definition and function call. You can replace it by a normal function call:

function getClickHandler(i) {
    return function() {
         /* Some code using i */
    }
}

for(var i=0; i < someArray.length; i++){
   someArray[i].onclick = getClickHandler(i);
}