d3.js. Spinning globe with bars

前端 未结 3 1589

I am trying to create spinning globe with bars like in this example. You can see my example here. And everything goes fine until bars go over horizon. I have no idea how to cut

相关标签:
3条回答
  • 2021-02-04 18:01

    To clip off the bars at the horizon, we add a mask centered at the globe 2D center and with it's radius. Then we apply this mask only if the bottom edge crosses the horizon (by tracking the longitude).

    Creating the mask

    // get the center of the circle
    var center = planetProjection.translate();
    // edge point
    var edge = planetProjection([-90, 90])
    // radius
    var r = Math.pow(Math.pow(center[0] - edge[0], 2) + Math.pow(center[1] - edge[1], 2), 0.5);
    
    svg.append("defs")
        .append("clipPath")
        .append("circle")
        .attr("id", "edgeCircle")
        .attr("cx", center[0])
        .attr("cy", center[1])
        .attr("r", r)
    
    var mask = svg.append("mask").attr("id", "edge")
    mask.append("rect")
        .attr("x", 0)
        .attr("y", 0)
        .attr("width", "100%")
        .attr("height", "100%")
        .attr("fill", "white");
    mask.append("use")
        .attr("xlink:href", "#edgeCircle")
        .attr("fill", "black");
    

    Applying the mask

    .... bars ....
    .attr("mask", function (d) {
        // make the range from 0 to 360, so that it's easier to compare
        var longitude = Number(d.Longitude) + 180;
        // +270 => -90 => the position of the left edge when the center is at 0
        // -value because a rotation to the right => left edge longitude is reducing
        // 360 because we want the range from 0 to 360
        var startLongitude = 360 - ((longitudeScale(current) + 270) % 360);
        // the right edge is start edge + 180
        var endLongitude = (startLongitude + 180) % 360;
        if ((startLongitude < endLongitude && longitude > startLongitude && longitude < endLongitude) ||
            // wrap around
            (startLongitude > endLongitude && (longitude > startLongitude || longitude < endLongitude)))
            return null;
        else
            return "url(#edge)";
    });
    

    We could also do this by measuring the distance.


    Fiddle - http://jsfiddle.net/gp3wvm8o/


    0 讨论(0)
  • 2021-02-04 18:07

    A simpler method that works with canvas would be to:

    1. Draw all the bars without clipping
    2. Draw the map
    3. Draw only the foreground bars (i.e., use clipping)

    This clipping does not have to be down manually but can leverage the path.centroid method which respects the clipping set on the projections by clipAngle. Pseudo code might look like:

    let projection = d3.geoOrthographic()
                   .clipAngle(90)
                   ...
    let barProjection = d3.geoOrthographic()
                   .clipAngle(90)
                   ...
    
    let path = d3.geoPath()
             .projection(projection)
             .context(canvasCtx)
    let barPath = d3.geoPath()
             .projection(barProjection)
    
    let renderBar = function(isBgLayer = false) {
        let barLengthAsScale = ...
        barProjection.scale(barLengthAsScale)
        let barStart, barEnd
        if (isBgLayer) {
            barStart = projection([ lon, lat ])
            barEnd = barProjection([ lon, lat ])
        } else {
            let geoJs = { type: 'Point', coordinates: [ lon, lat ] }
            barStart = path.centroid(geoJs)
            barEnd = barPath.centroid(geoJs)
        }
        // draw line from start to end using canvasCtx
    };
    
    let renderMap = function(topology) {
        // normal map drawing to canvas
    };
    
    // then to render a frame
    renderBar(true)
    renderMap(topoJsonTopology)
    renderBar()
    

    Some bars will be drawn twice, but with I've found that canvas is fast enough to keep up with the drawing and keep animations smooth with at least 200+ bars.

    For an example, check out this code on GitHub and the live page.

    0 讨论(0)
  • 2021-02-04 18:23

    Just keep track of the range of visible longitudes and hide the bars if they are not in that range

    .attr("display", function(d) {
        // make the range from 0 to 360, so that it's easier to compare
        var longitude = Number(d.Longitude) + 180;
        // +270 => -90 => the position of the left edge when the center is at 0
        // -value because a rotation to the right => left edge longitude is reducing
        // 360 because we want the range from 0 to 360
        var startLongitude = 360 - ((longitudeScale(current) + 270) % 360);
        // the right edge is start edge + 180
        var endLongitude = (startLongitude + 180) % 360;
        if ((startLongitude < endLongitude && longitude > startLongitude && longitude < endLongitude) ||
            // wrap around
            (startLongitude > endLongitude && (longitude > startLongitude || longitude < endLongitude)))
            return "block";
        else
            return "none";
    })
    

    Fiddle - http://jsfiddle.net/b12ryhda/

    0 讨论(0)
提交回复
热议问题