I have written an AWS Lambda Handler as below :
package com.lambda;
import com.amazonaws.services.lambda.runtime.Context;
import com.amazonaws.services.lambda.r
If the file is located under resources folder, you can use it directly in lambda by using something like the following code:
final BufferedReader br = new BufferedReader(new FileReader("/flows/cancellation/MessageArray.json"));
I wanted to read a json file, you can have different use case, but the code works.
If the file in located under resources directory, then the following solution should work:
String fileName = "resources/config.json";
Path path = Paths.get(this.getClass().getResource("/").toURI());
Path resourceLocation = path.resolve(fileName);
try(InputStream configStream = Files.newInputStream(resourceLocation)) {
//use your file stream as you need.
}
Here the most important part is "resources/config.json", it must not be "/resources/config.json", because the file location is /var/task/resources/config.json in lambda, I checked.
Hope this helps who still face problem in reading file in aws lambda.
This is how I did it, let's say this is how your project structure looks like -
And you want to read the file config.properties which is inside the project-dir/resources directory.
The code for reading the content of the file would be -
InputStream input = null;
try {
Path path = Paths.get(PropertyUtility.class.getResource("/").toURI());
// The path for config file in Lambda Instance -
String resourceLoc = path + "/resources/config.properties";
input = new FileInputStream(resourceLoc);
} catch(Exception e) {
// Do whatever
}
If you are following this project structure and using this code, then it will work in AWS Lambda.
PropertyUtility is just a utility class that I have created to read the contents of the config file. The PropertyUtility class looks like this -
As you can see in the above code, the path of the config file is different in the local system and in Lambda Instance.
In your local machine, PropertyUtility.class.getResource("/") points to bin, that is why you have to do path.getParent(), to point it to the project-directory which is HelloLambda in this example.
For the Lambda Instance, PropertyUtility.class.getResource("/") points directly to the project-directory.
I have made following changes in my code and now its works perfect :
Majorly changed following two lines :
ClassLoader classLoader = getClass().getClassLoader();
File cityFile = new File(classLoader.getResource("City.db").getFile());
package com.lambda;
import com.amazonaws.services.lambda.runtime.Context;
import com.amazonaws.services.lambda.runtime.LambdaLogger;
import com.amazonaws.services.lambda.runtime.RequestStreamHandler;
import java.io.*;
public class TestDetailsHandler implements RequestStreamHandler {
public void handleRequest(InputStream input,OutputStream output,Context context){
// Get Lambda Logger
LambdaLogger logger = context.getLogger();
// Receive the input from Inputstream throw exception if any
ClassLoader classLoader = getClass().getClassLoader();
File cityFile = new File(classLoader.getResource("City.db").getFile());
FileInputStream fis = null;
try {
fis = new FileInputStream(cityFile);
System.out.println("Total file size to read (in bytes) : "
+ fis.available());
int content;
while ((content = fis.read()) != -1) {
// convert to char and display it
System.out.print((char) content);
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (fis != null)
fis.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}