How to write this query using JPA Criteria query?

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攒了一身酷
攒了一身酷 2021-02-04 14:39

Can anyone help me to get the JPA criteria query for the JPA query mentioned below.

SELECT p,l FROM Person p 
LEFT JOIN Language l ON (p.language = l.language an         


        
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2条回答
  • 2021-02-04 15:32

    Although the answer given by johncarl was accepted it doesn't look correct to me. The JavaDocs for CriteriaQuery.where() say:

    Modify the query to restrict the query result according to the specified boolean expression. Replaces the previously added restriction(s), if any.

    As I understand it, each of the following lines (giving restrictions) will override the restrictions given previously:

    criteria.where(builder.like(langJoin.get(Language_.locale), locale));
    criteria.where(builder.like(pRoot.get(Person_.name), name));
    criteria.where(builder.between(pRoot.get(Person_.time), startDate, endDate));
    

    This means that in the end only the last restriction (between start and end date) would remain.

    I threfore suggest following modifications to johncarl's answer:

    CriteriaBuilder builder = entityManager.getCriteriaBuilder();
    CriteriaQuery<Person> criteria = builder.createCriteria(Person.class);
    Root<Person> pRoot = criteria.from(Person.class);
    Join<Person, Language> langJoin = criteria.join("language", JoinType.LEFT);
    
    Predicate[] restrictions = new Predicate[] { 
        builder.like(langJoin.get(Language_.locale), locale),
        builder.like(pRoot.get(Person_.name), name),
        builder.between(pRoot.get(Person_.time), startDate, endDate)
    };
    
    criteria.where(builder.and(restrictions));
    
    criteria.orderBy(builder.asc(pRoot.get(Person_.name)));
    

    However, this code looks really ugly! Please, feel free to edit if it's wrong and comment it if you see a better solution! I'd be gracefull!

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  • 2021-02-04 15:33

    Assuming that Person has a relation to Language here's what you would do in older Hibernate:

    Criteria criteria = entityManager.createCriteria(Person.class);
    Criteria languageCriteria = criteria.createCriteria("language");
    
    languageCriteria.add(Restrictions.like("locale", locale));
    
    criteria.add(Restrictions.like("name", name));
    criteria.add(Restrictions.between("time", startDate, endDate));
    
    criteria.addOrder(Order.asc("name"));
    

    and my first try at JPA 2.0:

    CriteriaBuilder builder = entityManager.getCriteriaBuilder();
    CriteriaQuery<Person> criteria = builder.createCriteria(Person.class);
    Root<Person> pRoot = criteria.from(Person.class);
    Join<Person, Language> langJoin = criteria.join("language", JoinType.LEFT);
    
    Predicate conjunction = builder.conjunction();
    
    criteria.where(builder.and(
        builder.like(langJoin.get(Language_.locale), locale),
        builder.like(pRoot.get(Person_.name), name),
        builder.between(pRoot.get(Person_.time), startDate, endDate));
    
    criteria.orderBy(builder.asc(pRoot.get(Person_.name)));
    

    Please let me know if that works for you.

    Edit: Updated query to use only one where call.

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