I have a few massive SQL request involving join across various models in my rails application. A single request can involve 6 to 10 tables.
To run the request faster I w
OK so my main problem was that you can't join a Arel::SelectManager ... BUT you can join a table aliasing. So to generate the request in my comment above:
a = A.arel_table
b = B.arel_table
subquery = B.select(:a_id).where{c > 4}
query = A.join(subquery.as('B')).on(b[:a_id].eq(a[:id])
query.to_sql # SELECT A.* INNER JOIN (SELECT B.a_id FROM B WHERE B.c > 4) B ON A.id = B.a_id
Was looking for this, and was helped by the other answers, but there are some error in both, e.g. A.join(...
should be a.join(...
.
And I also missed how to build an ActiveRecord::Relation
.
Here is how to build an ActiveRecord::Relation
, in Rails 4
a = A.arel_table
b = B.arel_table
subsel = B.select(b[:a_id]).where(b[:c].gt('4')).as('sub_select')
joins = a.join(subsel).on(subsel[:a_id].eq(a[:id])).join_sources
rel = A.joins(joins)
rel.to_sql
#=> "SELECT `a`.* FROM `a` INNER JOIN (SELECT `b`.`a_id` FROM `b` WHERE (`b`.`c` > 4)) sub_select ON sub_select.`a_id` = `a`.`id`"
Pierre, I thought a better solution could be the following (inspiration from this gist):
a = A.arel_table
b = B.arel_table
subquery = b.project(b[:a_id].as('A_id')).where{c > 4}
subquery = subquery.as('intm_table')
query = A.join(subquery).on(subquery[:A_id].eq(a[:id]))
No particular reason for naming the alias as "intm_table", I just thought it would be less confusing.