I am trying to make a selection from a MySQL database using the syntax WHERE col LIKE \'%\'
but I want to select even NULL
values with that query. Is t
Use COALESCE instead of IFNULL if you want to use it with java createQuery
WHERE COALESCE (xxx, '') LIKE '%'
If you want column1 LIKE '%' and want column1 IS NULL, why not just drop the WHERE clause?
Try:
SELECT * FROM TABLE;
Here's what I tried:
mysql> create table foo (a char(30));
Query OK, 0 rows affected (0.02 sec)
mysql> insert into foo values ( '' );
Query OK, 1 row affected (0.01 sec)
mysql> insert into foo values ( NULL );
Query OK, 1 row affected (0.00 sec)
mysql> select * from foo;
+------+
| a |
+------+
| |
| NULL |
+------+
2 rows in set (0.00 sec)
mysql> select * from foo where a like '%' or a is null;
+------+
| a |
+------+
| |
| NULL |
+------+
2 rows in set (0.00 sec)
mysql> select * from foo where ifnull (a, 1) like '%';
+------+
| a |
+------+
| |
| NULL |
+------+
2 rows in set (0.00 sec)
mysql>
After all, IFNULL(column1, 1) LIKE '%' is effectively a NO-OP ...
This statement returns all rows EXCEPT rows which have NULL in column1
SELECT * FROM table WHERE column1 LIKE '%'
To get all rows including rows with NULL in column1, use this:
SELECT * FROM table WHERE IFNULL(column1,1) LIKE '%'
from the MySQL documentation:
IFNULL(expr1,expr2)
If expr1 is not NULL, IFNULL() returns expr1; otherwise it returns expr2. IFNULL() returns a numeric or string value, depending on the context in which it is used.
There's one caveat however: If you have an index on column1, it won't be used in this query, so things could get slow in larger tables...
Use the IFNULL operator
WHERE IFNULL(xxx, '') LIKE '%'
SELECT * FROM table WHERE (job LIKE '%' OR job IS NULL)