Using list comprehension in Python to do something similar to zip()?

Question

I\'m a Python newbie and one of the things I am trying to do is wrap my head around list comprehension. I can see that it\'s a pretty powerful feature that\'s worth learning.

Answer 1

A list comprehension, without some help from zip, map, or itertools, cannot institute a "parallel loop" on multiple sequences -- only simple loops on one sequence, or "nested" loops on multiple ones.

Answer 2

Possible to use enumerate, as well:

[[y,airports[x]] for x,y in enumerate(cities)]

Answer 3

If you wanted to do it without using zip at all, you would have to do something like this:

[ [cities[i],airports[i]] for i in xrange(min(len(cities), len(airports))) ]

but there is no reason to do that other than an intellectual exercise.

Using map(list, zip(cities, airports)) is shorter, simpler and will almost certainly run faster.

Answer 4

This takes zip's output and converts all tuples to lists:

map(list, zip(cities, airports))

As for the performance of each:

$ python -m timeit -c '[ [a, b] for a, b in zip(xrange(100), xrange(100)) ]'
10000 loops, best of 3: 68.3 usec per loop

$ python -m timeit -c 'map(list, zip(xrange(100), xrange(100)))'
10000 loops, best of 3: 75.4 usec per loop

$ python -m timeit -c '[ list(x) for x in zip(range(100), range(100)) ]'
10000 loops, best of 3: 99.9 usec per loop

Answer 5

Something like this:

[[c, a] for c, a in zip(cities, airports)]

Alternately, the list constructor can convert tuples to lists:

[list(x) for x in zip(cities, airports)]

Or, the map function is slightly less verbose in this case:

map(list, zip(cities, airports))