Below is my Table
Table1
+--------+----------+---------+
| amount | make | product |
+--------+----------+---------+
| 100 | Nokia | Mo
select top 2 amount, make, product from table1
where product='Mobiles'
order by amount desc
union
select top 2 amount, make, product from table1
where product='Gift'
order by amount desc
select product, make, amount, rnk
from (
select l.product, l.make, l.amount, count(*) as rnk
from table1 as l
left join table1 as r
on (r.product = l.product and l.amount <= r.amount)
group by l.product, l.make
) a
where rnk <= 2
see the ideea and other examples here: http://www.xaprb.com/blog/2005/09/27/simulating-the-sql-row_number-function/
and sql fiddle based on zane bien test data.
SELECT a.*
FROM Table1 a
INNER JOIN Table1 b ON a.product = b.product AND a.amount <= b.amount
GROUP BY a.amount, a.product
HAVING COUNT(*) <= 2
ORDER BY a.amount desc
Please refer to http://sqlfiddle.com/#!2/9ba82/1
You can do it in two ways: 1) Add Row Index column that will reflect the order and then select all rows with Row <= 2
SELECT amount, make,product
FROM
(SELECT ROW_NUMBER() OVER (PARTITION BY [product] ORDER BY [amount] DESC) AS [RowID],*
FROM [dbo].[Table1]) RESULT
WHERE RowID <= 2
2) You can also join the table to itself
SELECT a1.* FROM Table1 AS a1
LEFT JOIN Table1 AS a2
ON a1.product = a2.product AND a1.amount<= a2.amount
GROUP BY a1.product
HAVING COUNT(*) <= 2;
You can use this solution to retrieve the "group-wise maximum" based on the amount
:
SELECT a.*
FROM Table1 a
INNER JOIN Table1 b ON a.product = b.product AND a.amount <= b.amount
GROUP BY a.amount, a.product
HAVING COUNT(*) <= 2
Simply change the 2
to however many of the top rows you want to retrieve per product.
If you wanted to retrieve the lowest two rows per product, you can simply change the <=
sign in the INNER JOIN
to a >=
.
You can fiddle around with this solution here: SQL-Fiddle Demo