Ordering items with matching tags by number of tags that match

Question

I\'m trying to figure out how to order items with matching tags by the number of tags that match.

Let\'s say you have three MySQL tables:

• tags(tag_id

Answer 1

Try something like this:

select article_id, count(tag_id) as common_tag_count
from articles_tags 
group by tag_id
where tag_id in (
    select tag_id from articles_tags where article_id = 2
) and article_id != 2
order by common_tag_count desc;

Syntax may need a little tweaking for MySQL.

or this one that actually works: ;-)

SELECT at1.article_id, Count(at1.tag_id) AS common_tag_count
FROM articles_tags AS at1 INNER JOIN articles_tags AS at2 ON at1.tag_id = at2.tag_id
WHERE at2.article_id = 2
GROUP BY at1.article_id
HAVING at1.article_id != 2
ORDER BY Count(at1.tag_id) DESC;

Answer 2

Something resembling:

SELECT a.* 
FROM articles AS a 
INNER JOIN articles_tags AS at ON a.id=at.article_id
INNER JOIN tags AS t ON at.tag_id = t.id
WHERE t.title = 'funny' OR t.title = 'goofy' OR t.title = 'silly' AND a.id != <article_id>
GROUP BY a.id
ORDER BY COUNT(a.id) DESC

With just the usual indexes, assuming articles_tags has PK of (article_id, tag_id), and an index on tags.title