EntityManager persist() method does not insert record to database

Question

I have problem with using EntityManager.persist(Object) method. Now when i get rid of other problems, by app work without Exception but object is not put in my data

Answer 1

You can open the new Transaction and then commit your records.

@PersistenceUnit(unitName = "NameOfPersistenceUnit")
private EntityManagerFactory entityManagerFactory;

void someMethod(AccountCommodity accountCommodity){
     EntityManager entityManager = entityManagerFactory.createEntityManager();
     entityManager.getTransaction().begin();
     entityManager.persist(accountCommodity);
     entityManager.flush();
     entityManager.getTransaction().commit();
     entityManager.close();
}

Answer 2

You will need to assign id generation strategy as below:

@Entity
@Table(name ="Chain")
public class Chain implements Serializable{

@Id
@Column(name = "id")
    @GeneratedValue(strategy=GenerationType.IDENTITY)
  private Long id;
@Column(name = "date")
  private Date date;
@Column(name = "name")
  private String name;
//setters and getters
}

and in save method

  public int saveChain(Chain chain) {
        chain.setDate(new Date());
      //chain.setId((long)44);  remove this line
        Boolean a;
        em.persist(chain);

        return 222;
    }

if you assign Id, then hibernate/jpa will try to update record, which is not available, instead of inserting new record and I think will not throw exception.

Answer 3

Adding these to your web.xml may solve this problem:

<!-- Open Entity Manager in View filter -->
<filter>
    <filter-name>openEntityManagerInViewFilter</filter-name>
    <filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
</filter>
<filter-mapping>
    <filter-name>openEntityManagerInViewFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

Answer 4

Use @EnableTransactionManagement in AppConfig Configuration file header

Answer 5

Can you post what exception are you getting? I will assume that your error is that your persistence.xml you don't specified your "Chain" Object.

You can specify using this tag

<exclude-unlisted-classes>false</exclude-unlisted-classes>

Or just

 <class>your.package.Chain</class>

Put this above provider tag.

Also, never set a number for a column tagged as @Id

When you use method save() with a Id column with setted value, hibernate will try to UPDATE NOT INSERT your data.

Do this: Create getEntityManager Method

public EntityManager getEntityManager() {
    return entityManager;
}

Then

@Transactional
public void saveChain(Chain chain) {

    chain.setDate(new Date());
    getEntityManager().persist(chain);
}

Answer 6

solved my problem using

org.springframework.transaction.jta.JtaTransactionManager

hope this work!