REST. Jersey. How to programmatically choose what type to return: JSON or XML?

Question

I have 2 questions:

1. Can I create one class, annotate it with JAXB annotations(for XML support) and declare in web.xml

Answer 1

If your client wants to use a part of the URL to configure the response type, you can use a Servlet filter.

An easy way to implement overriding the representation (media type) could use a URL query parameter:

/resources/todo?format=json

The Servlet filter parses the URL query parameters, and if a format=json is present, replaces or adds the accept header "application/json".

Answer 2

No need for seperate classes, what you need is seperate methods:

@GET
@Produces({ MediaType.APPLICATION_XML, MediaType.APPLICATION_JSON })
public Todo getXML() {
    Todo todo = new Todo();
    todo.setSummary("This is my first todo");
    todo.setDescription("This is my first todo");
    return todo;
}

Then in the client side, when you request for the service, you indicate in what format you want it:

// Get XML
System.out.println(service.path("rest").path("todo").accept(MediaType.TEXT_XML).get(String.class));
// Get XML for application
System.out.println(service.path("rest").path("todo").accept(MediaType.APPLICATION_XML).get(String.class));
// Get JSON for application
System.out.println(service.path("rest").path("todo").accept(MediaType.APPLICATION_JSON).get(String.class));

Answer 3

Note: I'm the EclipseLink JAXB (MOXy) lead and a member of the JAXB (JSR-222) expert group.

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Can I create one class, annotate it with JAXB annotations(for XML support) and declare in web.xml for JSON (Jackson library) support?

You can always use an Application class to specify a MessageBodyReader/MessageBodyWriter for the JSON binding. I believe Jackson provides an implementation in its jar. Below is an example of an Application class that specifies MOXy as the JSON provider:

package org.example;

import java.util.*;
import javax.ws.rs.core.Application;
import org.eclipse.persistence.jaxb.rs.MOXyJsonProvider;

public class CustomerApplication  extends Application {

    @Override
    public Set<Class<?>> getClasses() {
        HashSet<Class<?>> set = new HashSet<Class<?>>(2);
        set.add(MOXyJsonProvider.class);
        set.add(CustomerService.class);
        return set;
    }

}

Or I need to create separately two classes for JSON and XML?

EclipseLink JAXB (MOXy) offers native XML binding and is designed to enable you to use the same object model for both JSON and XML. You can integrate it into your JAX-RS application using the MOXyJsonProvider class:

• http://blog.bdoughan.com/2012/05/moxy-as-your-jax-rs-json-provider.html

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How I can programmatically choose what type to return (JSON or XML)?

Server Side

You can specify that your service offers both XML and JSON messages using the @Produces annotation.

@GET
@Produces({MediaType.APPLICATION_XML, MediaType.APPLICATION_JSON})
@Path("{id}")
public Customer read(@PathParam("id") long id) {
    return entityManager.find(Customer.class, id);
}

For More Information

• http://blog.bdoughan.com/2012/03/moxy-as-your-jax-rs-json-provider.html

Client Side

You can use the MediaType to indicate the type of message. Below is an example using Jersey client APIs. Note how the URL is the same, just the requested media type is different.

Client client = Client.create();
WebResource resource = client.resource("http://localhost:8080/CustomerService/rest/customers");

// Get XML response as a Customer
Customer customer = resource.path("1")
    .accept(MediaType.APPLICATION_XML)
        .get(Customer.class);
System.out.println(customer.getLastName() + ", "+ customer.getFirstName());

// Get JSON response as a Customer
Customer customer = resource.path("1")
    .accept(MediaType.APPLICATION_JSON)
        .get(Customer.class);
System.out.println(customer.getLastName() + ", "+ customer.getFirstName());

For More Information

• http://blog.bdoughan.com/2010/08/creating-restful-web-service-part-55.html