Django - DatabaseError: No such table

Question

I defined two models:

class Server(models.Model):
    owners = models.ManyToManyField(\'Person\')

class Person(models.Model):
    name = models.CharField(max_le         


        

Answer 1

Actually the problem was that the table never got created. Since I am fairly new with django, I did not know that ./manage.py syncdb does not update existing models, but only creates the ones that do not exist.

Because the model 'Server' existed before I added the other model, and it was already in the db, 'syncdb' did not actually create the new tables.

Answer 2

for django 1.9, this is what i did and it solved the issue.

python manage.py makemigrations app_name

python manage.py migrate

Answer 3

1. use "manage.py help" to check the command
2. if you find migrate and makemigration, it means your python has updated

step 1:

python manage.py makemigration

result 1:

Migrations for 'mainsite':
mainsite\migrations\0001_initial.py
- Create model Post

step 2:

python manage.py migrate

result 2:

Operations to perform:
Apply all migrations: admin, auth, contenttypes, mainsite, sessions
Running migrations:
Applying mainsite.0001_initial... OK

finally, runserver. Done

Answer 4

I meet the same problem today and fix it. I think you miss some command in tutorial 1. just do follow:

./python manage.py makemigrations polls
python manage.py sql polls
./python manage.py syncdb

then fix it and gain the table polls and you can see the table created. you should read the manage.py makemigrations command.

Answer 5

As a tip for the future, look into South, a very useful utility for applying your model changes to the database without having to create a new database each time you've changed the model(s).

With it you can easily: python manage.py migrate app_name and South will write your model changes. The documentation is pretty straightforward.