Consider the code given here,
https://spark.apache.org/docs/1.2.0/ml-guide.html
import org.apache.spark.ml.classification.LogisticRegression
val training
DataFrame
is a distributed data structure. It is neither required nor possible to parallelize
it. SparkConext.parallelize
method is used only to distributed local data structures which reside in the driver memory. You shouldn't be used to distributed large datasets not to mention redistributing RDDs
or higher level data structures (like you do in your previous question)
sc.parallelize(trainingData.collect())
If you want to convert between RDD
/ Dataframe
(Dataset
) use methods which are designed to do it:
from DataFrame
to RDD
:
import org.apache.spark.sql.DataFrame
import org.apache.spark.sql.Row
import org.apache.spark.rdd.RDD
val df: DataFrame = Seq(("foo", 1), ("bar", 2)).toDF("k", "v")
val rdd: RDD[Row] = df.rdd
form RDD
to DataFrame
:
val rdd: RDD[(String, Int)] = sc.parallelize(Seq(("foo", 1), ("bar", 2)))
val df1: DataFrame = rdd.toDF
// or
val df2: DataFrame = spark.createDataFrame(rdd) // From 1.x use sqlContext
You should maybe check out the difference between RDD and DataFrame and how to convert between the two: Difference between DataFrame and RDD in Spark
To answer your question directly: A DataFrame is already optimized for parallel execution. You do not need to do anything and you can pass it to any spark estimators fit() method directly. The parallel executions are handled in the background.