How to create a string-type variable in C

Question

Question

How to declare a string variable in C?

Background

In my quest to learn the basics of c, I am trying to port on

Answer 1

Normally we use "&" in scanf but you shouldn't use it before variable "name" here. Because "name" is a char array. When the name of a char array is used without "[]", it means the address of the array.

Answer 2

The int your putting is not a string, a string looks like "char myString[20]". Not like "int name", that's an integer and not a string or char. This is the code you want:

         int main(int argc, const char * argv[])
{

char name[9999];
printf("What is your name?\n");
scanf("%s", name);
system("cls");
printf("Your name is %s", name);

return 0;
}

Answer 3

char name[60];
scanf("%s", name);

Edit: restricted input length to 59 characters (plus terminating 0):

char name[60];
scanf("%59s", name);

Answer 4

It's easy!

Just put this line below, atop of your main() function.

typedef string char*;

This allows you to create a string variable as you do with integers or characters in C. After that, your program should look like this:

#include <stdio.h>

typedef char* string;

int main(void) {
    string a = "Hello";
    printf("%s\n", a);  // %s format specifier for String
    return 0;
}

For a live demonstration, visit this REPL.it.

Answer 5

C does not have a string variable type. Strings can be stored as character arrays (char variable type). The most basic example I would add up to the rest is:

int main()
{
   char name[] = "Hello World!";
   printf("%s",name);
   return(0);
}

Answer 6

In C you can not direct declare a string variable like Java and other language. you'll have to use character array or pointer for declaring strings.

char a[50];
printf("Enter your string");
gets(a);

OR

char *a;
printf("Enter your string here");
gets(a);

OR

char a[60];
scanf("%59s",a);