How do I convert a UIColor to a hexadecimal string?

Question

I have a project where I need to store the RGBA values of a UIColor in a database as an 8-character hexadecimal string. For example, [UIColor blueColor] would be @\"0000FFFF\".

Answer 1

Here it goes. Returns a NSString (e.g. ffa5678) with a hexadecimal value of the color.

- (NSString *)hexStringFromColor:(UIColor *)color
{
    const CGFloat *components = CGColorGetComponents(color.CGColor);

    CGFloat r = components[0];
    CGFloat g = components[1];
    CGFloat b = components[2];

    return [NSString stringWithFormat:@"%02lX%02lX%02lX",
            lroundf(r * 255),
            lroundf(g * 255),
            lroundf(b * 255)];
}

Answer 2

Swift 4 answer by extension UIColor:

extension UIColor {
    var hexString: String {
        let colorRef = cgColor.components
        let r = colorRef?[0] ?? 0
        let g = colorRef?[1] ?? 0
        let b = ((colorRef?.count ?? 0) > 2 ? colorRef?[2] : g) ?? 0
        let a = cgColor.alpha

        var color = String(
            format: "#%02lX%02lX%02lX",
            lroundf(Float(r * 255)),
            lroundf(Float(g * 255)),
            lroundf(Float(b * 255))
        )
        if a < 1 {
            color += String(format: "%02lX", lroundf(Float(a)))
        }
        return color
    }
}

Answer 3

Get your floats converted to int values first, then format with stringWithFormat:

    int r,g,b,a;

    r = (int)(255.0 * rFloat);
    g = (int)(255.0 * gFloat);
    b = (int)(255.0 * bFloat);
    a = (int)(255.0 * aFloat);

    [NSString stringWithFormat:@"%02x%02x%02x%02x", r, g, b, a];