How to find duplicate filenames (recursively) in a given directory? BASH

Question

I need to find every duplicate filenames in a given dir tree. I dont know, what dir tree user will give as a script argument, so I dont know the directory hierarchy. I tried thi

Answer 1

Here is another solution (based on the suggestion by @jim-mcnamara) without awk:

Solution 1

#!/bin/sh 
dirname=/path/to/directory
find $dirname -type f | sed 's_.*/__' | sort|  uniq -d| 
while read fileName
do
find $dirname -type f | grep "$fileName"
done

However, you have to do the same search twice. This can become very slow if you have to search a lot of data. Saving the "find" results in a temporary file might give a better performance.

Solution 2 (with temporary file)

#!/bin/sh 
dirname=/path/to/directory
tempfile=myTempfileName
find $dirname -type f  > $tempfile
cat $tempfile | sed 's_.*/__' | sort |  uniq -d| 
while read fileName
do
 grep "/$fileName" $tempfile
done
#rm -f $tempfile

Since you might not want to write a temp file on the harddrive in some cases, you can choose the method which fits your needs. Both examples print out the full path of the file.

Bonus question here: Is it possible to save the whole output of the find command as a list to a variable?