How to use PostgreSQL hstore/json with JdbcTemplate

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借酒劲吻你
借酒劲吻你 2021-02-04 07:47

Is there a way to use PostgreSQL json/hstore with JdbcTemplate? esp query support.

for eg:

hstore:

INSERT INTO hstore_test (data) V         


        
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  • 2021-02-04 08:11

    Even easier than JdbcTemplate, you can use the Hibernate Types open-source project to persist HStore properties.

    First, you need the Maven dependency:

    <dependency>
        <groupId>com.vladmihalcea</groupId>
        <artifactId>hibernate-types-52</artifactId>
        <version>${hibernate-types.version}</version>
    </dependency>
    

    Then, assuming you have the following Book entity:

    @Entity(name = "Book")
    @Table(name = "book")
    @TypeDef(name = "hstore", typeClass = PostgreSQLHStoreType.class)
    public static class Book {
     
        @Id
        @GeneratedValue
        private Long id;
     
        @NaturalId
        @Column(length = 15)
        private String isbn;
     
        @Type(type = "hstore")
        @Column(columnDefinition = "hstore")
        private Map<String, String> properties = new HashMap<>();
     
        //Getters and setters omitted for brevity
    }
    

    Notice that we annotated the properties entity attribute with the @Type annotation and we specified the hstore type that was previously defined via @TypeDef to use the PostgreSQLHStoreType custom Hibernate Type.

    Now, when storing the following Book entity:

    Book book = new Book();
     
    book.setIsbn("978-9730228236");
    book.getProperties().put("title", "High-Performance Java Persistence");
    book.getProperties().put("author", "Vlad Mihalcea");
    book.getProperties().put("publisher", "Amazon");
    book.getProperties().put("price", "$44.95");
     
    entityManager.persist(book);
    

    Hibernate executes the following SQL INSERT statement:

    INSERT INTO book (isbn, properties, id)
    VALUES (
        '978-9730228236',
        '"author"=>"Vlad Mihalcea",
         "price"=>"$44.95", "publisher"=>"Amazon",
         "title"=>"High-Performance Java Persistence"',
        1
    )
    

    And, when we fetch the Book entity, we can see that all properties are fetched properly:

    Book book = entityManager
    .unwrap(Session.class)
    .bySimpleNaturalId(Book.class)
    .load("978-9730228236");
     
    assertEquals(
        "High-Performance Java Persistence",
        book.getProperties().get("title")
    );
    
    assertEquals(
        "Vlad Mihalcea",
        book.getProperties().get("author")
    );
    
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  • 2021-02-04 08:16

    Although quite late for an answer (for the insert part), I hope it might be useful someone else:

    Take the key/value pairs in a HashMap:

    Map<String, String> hstoreMap = new HashMap<>();
    hstoreMap.put("key1", "value1");
    hstoreMap.put("key2", "value2");
    
    PGobject jsonbObj = new PGobject();
    jsonbObj.setType("json");
    jsonbObj.setValue("{\"key\" : \"value\"}");
    

    use one of the following way to insert them to PostgreSQL:

    1)

    jdbcTemplate.update(conn -> {
         PreparedStatement ps = conn.prepareStatement( "INSERT INTO table (hstore_col, jsonb_col) VALUES (?, ?)" );
         ps.setObject( 1, hstoreMap );
         ps.setObject( 2, jsonbObj );
    });
    

    2)

    jdbcTemplate.update("INSERT INTO table (hstore_col, jsonb_col) VALUES(?,?)", 
    new Object[]{ hstoreMap, jsonbObj }, new int[]{Types.OTHER, Types.OTHER});
    

    3) Set hstoreMap/jsonbObj in the POJO (hstoreCol of type Map and jsonbObjCol is of type PGObject)

    BeanPropertySqlParameterSource sqlParameterSource = new BeanPropertySqlParameterSource( POJO );
    sqlParameterSource.registerSqlType( "hstore_col", Types.OTHER );
    sqlParameterSource.registerSqlType( "jsonb_col", Types.OTHER );
    namedJdbcTemplate.update( "INSERT INTO table (hstore_col, jsonb_col) VALUES (:hstoreCol, :jsonbObjCol)", sqlParameterSource );
    

    And to get the value:

    (Map<String, String>) rs.getObject( "hstore_col" ));
    ((PGobject) rs.getObject("jsonb_col")).getValue();
    
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