How to pass an object from one activity to another on Android

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遇见更好的自我
遇见更好的自我 2020-11-21 04:03

I am trying to work on sending an object of my customer class from one Activity and display it in another Activity.

The code for t

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  • 2020-11-21 04:59

    Start another activity from this activity and pass parameters via Bundle Object

    Intent intent = new Intent(getBaseContext(), YourActivity.class);
    intent.putExtra("USER_NAME", "xyz@gmail.com");
    startActivity(intent);
    

    Retrive data on another activity (YourActivity)

    String s = getIntent().getStringExtra("USER_NAME");
    

    This is ok for simple kind of data type. But if u want to pass complex data in between activity. U need to serialize it first.

    Here we have Employee Model

    class Employee{
        private String empId;
        private int age;
        print Double salary;
    
        getters...
        setters...
    }
    

    You can use Gson lib provided by google to serialize the complex data like this

    String strEmp = new Gson().toJson(emp);
    Intent intent = new Intent(getBaseContext(), YourActivity.class);
    intent.putExtra("EMP", strEmp);
    startActivity(intent);
    
    Bundle bundle = getIntent().getExtras();
    String empStr = bundle.getString("EMP");
                Gson gson = new Gson();
                Type type = new TypeToken<Employee>() {
                }.getType();
                Employee selectedEmp = gson.fromJson(empStr, type);
    
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  • 2020-11-21 05:00

    In my experience there are three main solutions, each with their disadvantages and advantages:

    1. Implementing Parcelable

    2. Implementing Serializable

    3. Using a light-weight event bus library of some sort (for example, Greenrobot's EventBus or Square's Otto)

    Parcelable - fast and Android standard, but it has lots of boilerplate code and requires hard-coded strings for reference when pulling values out the intent (non-strongly typed).

    Serializable - close to zero boilerplate, but it is the slowest approach and also requires hard-coded strings when pulling values out the intent (non-strongly typed).

    Event Bus - zero boilerplate, fastest approach, and does not require hard-coded strings, but it does require an additional dependency (although usually lightweight, ~40 KB)

    I posted a very detailed comparison around these three approaches, including efficiency benchmarks.

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  • 2020-11-21 05:01

    Create your own class Customer as following:

    import import java.io.Serializable;
    public class Customer implements Serializable
    {
        private String name;
        private String city;
    
        public Customer()
        {
    
        }
        public Customer(String name, String city)
        {
            this.name= name;
            this.city=city;
        }
        public String getName() 
        {
            return name;
        }
        public void setName(String name) 
        {
            this.name = name;
        }
        public String getCity() 
        {
            return city;
        }
        public void setCity(String city) 
        {
            this.city= city;
        }
    
    }
    

    In your onCreate() method

    @Override
    protected void onCreate(Bundle savedInstanceState) 
    {
        super.onCreate(savedInstanceState); 
        setContentView(R.layout.activity_top);
    
        Customer cust=new Customer();
        cust.setName("abc");
        cust.setCity("xyz");
    
        Intent intent=new Intent(abc.this,xyz.class);
        intent.putExtra("bundle",cust);
        startActivity(intent); 
    }
    

    In xyz activity class you need to use the following code:

    Intent intent=getIntent();
    Customer cust=(Customer)intent.getSerializableExtra("bundle");
    textViewName.setText(cust.getName());
    textViewCity.setText(cust.getCity());
    
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  • 2020-11-21 05:02

    Crete a class like bean class and implement the Serializable interface. Then we can pass it through the intent method, for example:

    intent.putExtra("class", BeanClass);
    

    Then get it from the other activity, for example:

    BeanClass cb = intent.getSerializableExtra("class");
    
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  • 2020-11-21 05:05

    Pass one activity to another:

    startActivity(new Intent(getBaseContext(),GetActivity.class).putExtra("passingkey","passingvalue"));
    

    Get values:

    String myvalue= getIntent().getExtras("passingkey");
    
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  • 2020-11-21 05:06
    1. I know that static is bad, but it seems that we're forced to use it here. The problem with parceables/seriazables is that the two activities have duplicate instances of the same object = waste of memory and CPU.

      public class IntentMailBox {
          static Queue<Object> content = new LinkedList<Object>();
      }
      

    Calling activity

    IntentMailBox.content.add(level);
    Intent intent = new Intent(LevelsActivity.this, LevelActivity.class);
    startActivity(intent);
    

    Called activity (note that onCreate() and onResume() may be called multiple times when the system destroys and recreates activities)

    if (IntentMailBox.content.size()>0)
        level = (Level) IntentMailBox.content.poll();
    else
        // Here you reload what you have saved in onPause()
    
    1. Another way is to declare a static field of the class that you want to pass in that very class. It will serve only for this purpose. Don't forget that it can be null in onCreate, because your app package has been unloaded from memory by system and reloaded later.

    2. Bearing in mind that you still need to handle activity lifecycle, you may want to write all the data straight to shared preferences, painful with complex data structures as it is.

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