Regular expression for Dutch zip / postal code

Question

I\'m trying to build a regular expression in javascript to validate a Dutch zipcode.

The zipcode should contain 4 numbers, then optionally a space and then 2 (case insen

Answer 1

In case you have trouble using this as pattern for bootstrap validation I suggest you change it to:

    ^[1-9][0-9]{3} ?(?!sa|sd|ss|SA|SD|SS)[A-Za-z]{2}$

This way it is still case-insensitive and accepted by the bootstrap validator.

Answer 2

Edited to handle no leading 0 requirement for Dutch postal codes, and to eliminate matches for SS, SA, and SD. This should do it all for you.

Final regex:

var rege = /^[1-9][0-9]{3} ?(?!sa|sd|ss)[a-z]{2}$/i;

Fiddle unit test: http://jsfiddle.net/hgU3u/

Here's a breakdown:

1. ^ matches beginning of string
2. [1-9][0-9]{3} matches a single non-zero digit, and three 0-9 digits
3. ? matches 0 or 1 spaces (you could use * to match 0 or more spaces)
4. (?!sa|sd|ss) is a lookahead test to check that the remainder is not "sa", "sd", or "ss".
5. [a-z]{2} matches 2 a-z characters
6. $ matches the end of the string
7. i at the end is the case-insensitive modifier

Answer 3

Here is my solution. The i in the end makes it case-insensitive:

var rege = /^\d{4} ?[a-z]{2}$/i;