C: Cannot initialize variable with an rvalue of type void*

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栀梦
栀梦 2021-02-04 05:30

I have the following code:

int *numberArray = calloc(n, sizeof(int));

And I am unable to understand why I receive the following error.

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  • 2021-02-04 06:03

    You're using C memory re-allocation style in a C++ code. What you want to use is new in C++

    So your code will become:

    int n = 10; //n = size of your array
    int *narray = new int[n];
    for (int i = 0; i < n; i++)
        cout << narray[i];
    

    Alternatively you can switch back to C and use calloc with casting.

    int* numberArray = (int*)calloc(n, sizeof(int));
    
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  • 2021-02-04 06:10

    The compiler's error message is very clear.

    The return value of calloc is void*. You are assigning it to a variable of type int*.

    That is ok in a C program, but not int a C++ program.

    You can change that line to

    int* numberArray = (int*)calloc(n, sizeof(int));
    

    But, a better alternative will be to use the new operator to allocate memory. After all, you are using C++.

    int* numberArray = new int[n];
    
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  • 2021-02-04 06:12
    void* calloc (size_t num, size_t size);
    

    Allocate and zero-initialize array. Allocates a block of memory for an array of num elements, each of them size bytes long, and initializes all its bits to zero.The effective result is the allocation of a zero-initialized memory block of (num*size) bytes.

    On success, a pointer to the memory block allocated by the function. The type of this pointer is always void*, which can be cast to the desired type of data pointer in order to be dereferenceable. If the function failed to allocate the requested block of memory, a null pointer is returned.

    To summarize, since calloc returns a void* (generic pointer) on success of memory allocation, you will have to type-cast it like this in C++:

    int *numberArray = (int*)calloc(n, sizeof(int));
    

    If it was C, you can still skip this cast.

    Or, use new as:

    int *numberArray = new int [n];
    
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  • 2021-02-04 06:19

    Syntax for calloc is:

    void* calloc (size_t num, size_t size);

    calloc returns void pointer. In your code , you are trying to assign void pointer to integer pointer. So you are getting Cannot initialize a variable of type 'int *' with an rvalue of type 'void *'. So typecast the void pointer before assign it like this

    *numberArray = (int *) calloc(n, sizeof(int));

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