How to read multiple Integer values from a single line of input in Java?

Question

I am working on a program and I want to allow a user to enter multiple integers when prompted. I have tried to use a scanner but I found that it only stores the first intege

Answer 1

I use it all the time on hackerrank/leetcode

    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    String  lines = br.readLine();    
        
    String[] strs = lines.trim().split("\\s+");
            
    for (int i = 0; i < strs.length; i++) {
    a[i] = Integer.parseInt(strs[i]);
    }

Answer 2

created this code specially for the Hacker earth exam

  Scanner values = new Scanner(System.in);  //initialize scanner
  int[] arr = new int[6]; //initialize array 
  for (int i = 0; i < arr.length; i++) {
      arr[i] = (values.hasNext() == true ? values.nextInt():null);
      // it will read the next input value
  }

 /* user enter =  1 2 3 4 5
    arr[1]= 1
    arr[2]= 2
    and soo on 
 */ 

Answer 3

Scanner has a method called hasNext():

    Scanner scanner = new Scanner(System.in);

    while(scanner.hasNext())
    {
        System.out.println(scanner.nextInt());
    }

Answer 4

Java 8

BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
int arr[] = Arrays.stream(in.readLine().split(" ")).mapToInt(Integer::parseInt).toArray();

Answer 5

You're probably looking for String.split(String regex). Use " " for your regex. This will give you an array of strings that you can parse individually into ints.

Answer 6

It's working with this code:

Scanner input = new Scanner(System.in);
System.out.println("Enter Name : ");
String name = input.next().toString();
System.out.println("Enter Phone # : ");
String phone = input.next().toString();