Is the defaultdict in Python's collections module really faster than using setdefault?

Question

I\'ve seen other Python programmers use defaultdict from the collections module for the following use case:

from collections import defaultdict

s = [(\'yellow\'         


        

Answer 1

Yes, there is something "wrong":

You have put the creation of the (default)dict into the statement instead of the setup. Constructing a new defaultdict is more expensive than a normal dict, and usually that's not the bottleneck you should be profiling in a program - after all, you build your data structures once but you use them many times.

If you do your tests like below, you see that defaultdict operations are indeed faster:

>>> import timeit
>>> setup1 = """from collections import defaultdict
... s = [('yellow', 1), ('blue', 2), ('yellow', 3), ('blue', 4), ('red', 1)]
... d = defaultdict(list)"""
>>> stmt1 = """for k, v in s:
...     d[k].append(v)"""
>>> setup2 = """s = [('yellow', 1), ('blue', 2), ('yellow', 3), ('blue', 4), ('red', 1)]
... d = {}"""
>>> stmt2 = """for k, v in s:
...     d.setdefault(k, []).append(v)"""
>>> timeit.timeit(setup=setup1, stmt=stmt1)
1.0283400125194078
>>> timeit.timeit(setup=setup2, stmt=stmt2)
1.7767367580925395

Python 2.7.3 on Win7 x64.