I have a object like that one:
Object {a: 1, b: 2, undefined: 1}
How can I quickly pull the largest value identifier (here: b
const data = {
abc: '',
myShortKey: '',
myVeryLongKey: ''
}
const longestKeyLength = Math.max(...Object.keys(data).map((d) => d.length));
console.log(longestKeyLength);
console.log(Object.entries(data).map(([key, val]) => `${key}: ${key.length}`));
Supposing you've an Object
like this:
var obj = {a: 1, b: 2, undefined: 1}
You can do this
var max = Math.max.apply(null,Object.keys(obj).map(function(x){ return obj[x] }));
console.log(Object.keys(obj).filter(function(x){ return obj[x] == max; })[0]);
Using Underscore or Lo-Dash:
var maxKey = _.max(Object.keys(obj), function (o) { return obj[o]; });
With ES6 Arrow Functions:
var maxKey = _.max(Object.keys(obj), o => obj[o]);
jsFiddle demo
For example:
var obj = {a: 1, b: 2, undefined: 1};
Object.keys(obj).reduce(function(a, b){ return obj[a] > obj[b] ? a : b });
In ES6:
var obj = {a: 1, b: 2, undefined: 1};
Object.keys(obj).reduce((a, b) => obj[a] > obj[b] ? a : b);
Here is a suggestion in case you have many equal values and not only one maximum:
const getMax = object => {
return Object.keys(object).filter(x => {
return object[x] == Math.max.apply(null,
Object.values(object));
});
};
This returns an array, with the keys for all of them with the maximum value, in case there are some that have equal values. For example: if
const obj = {apples: 1, bananas: 1, pears: 1 }
//This will return ['apples', 'bananas', 'pears']
If on the other hand there is a maximum:
const obj = {apples: 1, bananas: 2, pears: 1 }; //This will return ['bananas']
---> To get the string out of the array: ['bananas'][0] //returns 'bananas'`
Very basic method. might be slow to process
var v = {a: 1, b: 2, undefined: 1};
function geth(o){
var vals = [];
for(var i in o){
vals.push(o[i]);
}
var max = Math.max.apply(null, vals);
for(var i in o){
if(o[i] == max){
return i;
}
}
}
console.log(geth(v));