JavaScript by reference vs. by value [duplicate]

Answer 1

My understanding is that this is actually very simple:

• Javascript is always pass by value, but when a variable refers to an object (including arrays), the "value" is a reference to the object.
• Changing the value of a variable never changes the underlying primitive or object, it just points the variable to a new primitive or object.
• However, changing a property of an object referenced by a variable does change the underlying object.

So, to work through some of your examples:

function f(a,b,c) {
    // Argument a is re-assigned to a new value.
    // The object or primitive referenced by the original a is unchanged.
    a = 3;
    // Calling b.push changes its properties - it adds
    // a new property b[b.length] with the value "foo".
    // So the object referenced by b has been changed.
    b.push("foo");
    // The "first" property of argument c has been changed.
    // So the object referenced by c has been changed (unless c is a primitive)
    c.first = false;
}

var x = 4;
var y = ["eeny", "miny", "mo"];
var z = {first: true};
f(x,y,z);
console.log(x, y, z.first); // 4, ["eeny", "miny", "mo", "foo"], false

Example 2:

var a = ["1", "2", {foo:"bar"}];
var b = a[1]; // b is now "2";
var c = a[2]; // c now references {foo:"bar"}
a[1] = "4";   // a is now ["1", "4", {foo:"bar"}]; b still has the value
              // it had at the time of assignment
a[2] = "5";   // a is now ["1", "4", "5"]; c still has the value
              // it had at the time of assignment, i.e. a reference to
              // the object {foo:"bar"}
console.log(b, c.foo); // "2" "bar"

Answer 2

1. Primitive type variable like string,number are always pass as pass by value.

2. Array and Object is passed as pass by reference or pass by value based on these two condition.

   • if you are changing value of that Object or array with new Object or Array then it is pass by Value.

     object1 = {item: "car"}; array1=[1,2,3];

   here you are assigning new object or array to old one.you are not changing the value of property of old object.so it is pass by value.

   • if you are changing a property value of an object or array then it is pass by Reference.

     object1.item= "car"; array1[0]=9;

   here you are changing a property value of old object.you are not assigning new object or array to old one.so it is pass by reference.

Code

    function passVar(object1, object2, number1) {

        object1.key1= "laptop";
        object2 = {
            key2: "computer"
        };
        number1 = number1 + 1;
    }

    var object1 = {
        key1: "car"
    };
    var object2 = {
        key2: "bike"
    };
    var number1 = 10;

    passVar(object1, object2, number1);
    console.log(object1.key1);
    console.log(object2.key2);
    console.log(number1);

Output: -
    laptop
    bike
    10

Answer 3

Javascript always passes by value. However, if you pass an object to a function, the "value" is really a reference to that object, so the function can modify that object's properties but not cause the variable outside the function to point to some other object.

An example:

function changeParam(x, y, z) {
  x = 3;
  y = "new string";
  z["key2"] = "new";
  z["key3"] = "newer";

  z = {"new" : "object"};
}

var a = 1,
    b = "something",
    c = {"key1" : "whatever", "key2" : "original value"};

changeParam(a, b, c);

// at this point a is still 1
// b is still "something"
// c still points to the same object but its properties have been updated
// so it is now {"key1" : "whatever", "key2" : "new", "key3" : "newer"}
// c definitely doesn't point to the new object created as the last line
// of the function with z = ...

Answer 4

Yes, Javascript always passes by value, but in an array or object, the value is a reference to it, so you can 'change' the contents.

But, I think you already read it on SO; here you have the documentation you want:

http://snook.ca/archives/javascript/javascript_pass