calling child class method from parent class file in python

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名媛妹妹
名媛妹妹 2021-02-04 01:01

parent.py:

class A(object):
    def methodA(self):
        print(\"in methodA\")

child.py:

from paren         


        
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  • 2021-02-04 01:44

    Doing this would only make sense if A is an abstract base class, meaning that A is only meant to be used as a base for other classes, not instantiated directly. If that were the case, you would define methodB on class A, but leave it unimplemented:

    class A(object):
        def methodA(self):
            print("in methodA")
    
        def methodB(self):
            raise NotImplementedError("Must override methodB")
    
    
    from parent import A
    class B(A):
        def methodB(self):
            print("am in methodB")
    

    This isn't strictly necessary. If you don't declare methodB anywhere in A, and instantiate B, you'd still be able to call methodB from the body of methodA, but it's a bad practice; it's not clear where methodA is supposed to come from, or that child classes need to override it.

    If you want to be more formal, you can use the Python abc module to declare A as an abstract base class.

    from abc import ABCMeta, abstractmethod
    
    class A(object):
     __metaclass__ = ABCMeta
    
        def methodA(self):
            print("in methodA")
    
        @abstractmethod
        def methodB(self):
            raise NotImplementedError("Must override methodB")
    

    Using this will actually prevent you from instantiating A or any class that inherits from A without overriding methodB. For example, if B looked like this:

    class B(A):
       pass
    

    You'd get an error trying to instantiate it:

    Traceback (most recent call last):
      File "<stdin>", line 1, in <module>
    TypeError: Can't instantiate abstract class B with abstract methods methodB
    

    The same would happen if you tried instantiating A.

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  • 2021-02-04 01:50

    You can do something like this:

    class A():
        def foo(self):
            self.testb()
    
    class B(A):
        def testb(self):
            print('lol, it works')
    b = B()
    b.foo()
    

    Which would return this of course:

    lol, it works
    

    Note, that in fact there is no call from parent, there is just call of function foo from instance of child class, this instance has inherited foo from parent, i.e. this is impossible:

    a=A()
    a.foo()
    

    will produce: AttributeError: A instance has no attribute 'testb'

    because

    >>> dir(A)
    ['__doc__', '__module__', 'foo']
    >>> dir(B)
    ['__doc__', '__module__', 'foo', 'testb']
    

    What I've wanted to show that you can create instance of child class, and it will have all methods and parameters from both parent and it's own classes.

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  • 2021-02-04 01:58

    You could use the function anywhere so long as it was attached to an object, which it appears to be from your sample. If you have a B object, then you can use its methodb() function from absolutely anywhere.

    parent.py:

    class A(object):
        def methoda(self):
            print("in methoda")
    
    def aFoo(obj):
      obj.methodb()
    

    child.py

    from parent import A
    class B(A):
        def methodb(self):
            print("am in methodb")
    

    You can see how this works after you import:

    >>> from parent import aFoo
    >>> from child import B
    >>> obj = B()
    >>> aFoo(obj)
    am in methodb
    

    Granted, you will not be able to create a new B object from inside parent.py, but you will still be able to use its methods if it's passed in to a function in parent.py somehow.

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  • 2021-02-04 02:00

    There are three approaches/ways to do this ! but I highly recommend to use the approach #3 because composition/decoupling has certain benefits in terms of design pattern. (GOF)

    ## approach 1 inheritance 
    class A():
        def methodA(self):
            print("in methodA")
        def call_mehtodB(self):
            self.methodb()
    
    class B(A):
        def methodb(self):
            print("am in methodb")
    
    b=B()
    b.call_mehtodB()
    
    
    ## approach 2 using abstract method still class highly coupled
    from abc import ABC, abstractmethod
    class A(ABC):
        def methodA(self):
            print("in methodA")
        @abstractmethod    
        def methodb(self):
           pass
    
    class B(A):
    
        def methodb(self):
            print("am in methodb")
    
    b=B()
    b.methodb()
    
    #approach 3 the recommended way ! Composition 
    
    class A():
        def __init__(self, message):
            self.message=message
    
        def methodA(self):
            print(self.message)
    
    class B():
        def __init__(self,messageB, messageA):
            self.message=messageB
            self.a=A(messageA)
    
        def methodb(self):
            print(self.message)
    
        def methodA(self):
            print(self.a.message)
    
    b=B("am in methodb", "am in methodA")
    b.methodb()
    b.methodA()
    
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  • 2021-02-04 02:01

    If the both class in same .py file then you can directly call child class method from parents class. It gave me warning but it run well.

    class A(object):

    def methodA(self):
    
        print("in methodA")
    
        Self.methodb()
    

    class B(A):

    def methodb(self):
    
        print("am in methodb")
    
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