I am using Python 2.7.5 @ Mac OS X 10.9.3 with 8GB memory and 1.7GHz Core i5. I have tested time consumption as below.
d = {i:i*2 for i in xrange(10**7*3)} #WARN
as opposed to using the system time
command, running in ipython with timeit
yields:
d = {i:i*2 for i in xrange(10**7*3)} #WARNING: it takes time and consumes a lot of RAM
timeit for k in d: k, d[k]
1 loops, best of 3: 2.46 s per loop
timeit for k, v in d.iteritems(): k, v
1 loops, best of 3: 1.92 s per loop
i ran this on windows, python 2.7.6. have you run it multiple times to confirm it wasn't something going on with the system itself?
To answer your question we should first dig some information about how and when iteritems()
was added to the API.
The iteritems() method was added in Python2.2 following the introduction of iterators and generators in the language (see also: What is the difference between dict.items() and dict.iteritems()?). In fact the method is explicitly mentioned in PEP 234. So it was introduced as a lazy alternative to the already present items().
This followed the same pattern as file.xreadlines() versus file.readlines() which was introduced in Python 2.1 (and already deprecated in python2.3 by the way).
In python 2.3 the itertools
module was added which introduced lazy counterparts to map, filter etc.
In other words, at the time there was (and still there is) a strong trend towards lazyness of operations. One of the reasons is to improve memory efficiency. An other one is to avoid unneeded computation.
I cannot find any reference that says that it was introduced to improve the speed of looping over the dictionary. It was simply used to replace calls to items()
that didn't actually have to return a list. Note that this include more use-cases than just a simple for
loop.
For example in the code:
function(dictionary.iteritems())
you cannot simply use a for
loop to replace iteritems()
as in your example. You'd have to write a function (or use a genexp, even though they weren't available when iteritems()
was introduced, and they wouldn't be DRY...).
Retrieving the items from a dict
is done pretty often so it does make sense to provide a built-in method and, in fact, there was one: items()
. The problem with items()
is that:
dict
can take quite some timedict
that contains most objects being manipulatedSo, when introducing iterators and generators, it was obvious to just add a lazy counterpart. If you need a list of items because you want to index it or iterate more than once, use items()
, otherwise you can just use iteritems()
and avoid the problems cited above.
The advantages of using iteritems()
are the same as using items()
versus manually getting the value:
Plus the advantages of lazyness.
As I already stated I cannot reproduce your performance results. On my machine iteritems()
is always faster than iterating + looking up by key. The difference is quite negligible anyway, and it's probably due to how the OS is handling caching and memory in general. In otherwords your argument about efficiency isn't a strong argument against (nor pro) using one or the other alternative.
Given equal performances on average, use the most readable and concise alternative: iteritems()
. This discussion would be similar to asking "why use a foreach when you can just loop by index with the same performance?". The importance of foreach isn't in the fact that you iterate faster but that you avoid writing boiler-plate code and improve readability.
I'd like to point out that iteritems()
was in fact removed in python3. This was part of the "cleanup" of this version. Python3 items() method id (mostly) equivalent to Python2's viewitems() method (actually a backport if I'm not mistaken...).
This version is lazy (and thus provides a replacement for iteritems()
) and has also further functionality, such as providing "set-like" operations (such as finding common items between dict
s in an efficient way etc.) So in python3 the reasons to use items()
instead of manually retrieving the values are even more compelling.
Using for k,v in d.iteritems()
with more descriptive names can make the code in the loop suite easier to read.
I know technically this is not an answer to the question, but the comments section is a poor place to put this sort of information. I hope that this helps people better understand the nature of the problem being discussed.
For thoroughness I've timed a bunch of different configurations. These are all timed using timeit
with a repetition factor of 10
. This is using CPython version 2.7.6 on Mac OS X 10.9.3 with 16GB memory and 2.3GHz Core i7.
python -m timeit -n 10 -s 'd={i:i*2 for i in xrange(10**7*3)}' 'for k in d: k, d[k]'
>> 10 loops, best of 3: 2.05 sec per loop
python -m timeit -n 10 -s 'd={i:i*2 for i in xrange(10**7*3)}' 'for k, v in d.iteritems(): k, v'
>> 10 loops, best of 3: 1.74 sec per loop
This suggestion involves passing in the iteritems
loop, and assigning a value to a variable v
in the first loop by accessing the dictionary at k
.
python -m timeit -n 10 -s 'd={i:i*2 for i in xrange(10**7*3)}' 'for k in d: v = d[k]'
>> 10 loops, best of 3: 1.29 sec per loop
python -m timeit -n 10 -s 'd={i:i*2 for i in xrange(10**7*3)}' 'for k, v in d.iteritems(): pass'
>> 10 loops, best of 3: 934 msec per loop
This one removes the assignment in the first loop but keeps the dictionary access. This is not a fair comparison because the second loop creates an additional variable and assigns it a value implicitly.
python -m timeit -n 10 -s 'd={i:i*2 for i in xrange(10**7*3)}' 'for k in d: d[k]'
>> 10 loops, best of 3: 1.27 sec per loop
Interestingly, the assignment is trivial to the access itself -- the difference being a mere 20 msec total. In every comparison (even the final, unfair one), the iteritems
wins out.
The times are closest, percentage wise, in the original configuration. This is probably due to the bulk of the work being creating a tuple (which is not assigned anywhere). Once that is removed from the equation, the differences between the two methods becomes more pronounced.
dict.iter() wins out heavily in python 3.5.
Here is a small performance stat:
d = {i:i*2 for i in range(10**3)}
timeit.timeit('for k in d: k,d[k]', globals=globals())
75.92739052970501
timeit.timeit('for k, v in d.items(): k,v', globals=globals())
57.31370617801076